Answer:
Relative frequency of selecting a 2 = 8/50 = 0.16
Relative frequency of selecting a 3 = 14/50 = 0.28
Step-by-step explanation:
When we have a given experiment with given outcomes (such that each time that we perform the experiment, one outcome happens) the relative frequency of a given outcome is the quotient between the number of times that that outcome happened, and the total number of times that the experiment was performed.
Here the experiment is selecting a random number between 1 and 5, and it is performed 50 times.
Out of these 50 times, the outcome "2" appears 8 times.
Then the relative frequency of selecting the number 2 is:
f(2) = 8/50 = 0.16
And of these 50 experiments, the outcome "3" appears 14 times.
Then the relative frequency of selecting the number 3 is:
f(3) = 14/50 = 0.28
Answer: 12.5 in. high
Step-by-step explanation: to get from 4 to 10, you have to muliplty by 2.5.
if you multiply 5 by 2.5, the answer is 12.5
Answer:
The missing reason is Subtraction Property of Equality.
Step-by-step explanation:
⇒ (Given)
On Solving we get;
Multiplying 2 on both side we get;
⇒ (Multiplication Property of Equality)
Now Subtracting Both side by 10 we get;
⇒ (Subtraction Property of Equality)
Now Dividing both side by 3 we get;
⇒ (Division Property of Equality)
Hence the missing reason is Subtraction Property of Equality.
Answer:
C
Step-by-step explanation:
Calculate AC using Pythagoras' identity in ΔABC
AC² = 20² - 12² = 400 - 144 = 256, hence
AC = 
= 16
Now find AD² from ΔACD and ΔABD
ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²
ΔABD → AD² = 12² - x² = 144 - x²
Equate both equations for AD², hence
256 - 400 + 40x - x² = 144 - x²
-144 + 40x - x² = 144 - x² ( add x² to both sides )
- 144 + 40x = 144 ( add 144 to both sides )
40x = 288 ( divide both sides by 40 )
x = 7.2 → C
Answer:
its B,C,and E
Step-by-step explanation:
