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butalik [34]
3 years ago
14

Round to the nearest hundredth

Mathematics
1 answer:
Artist 52 [7]3 years ago
8 0
They are already rounded?; unless you need to round lower
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A circus tent is cylindrical up to a height of 7 m and is in the shape of a cone over it, the diameter of the cylindrical part i
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\bold{\huge{\underline{ Solution }}}

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

• The circus tent is composed of cylinder and a cone.

• The height and diameter of the cylindrical part are 7m and 10m

• The total height of the circus tent 19m

• The cost of making the tent at a cost of 35 m² cloth.

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

<u>Here</u><u>, </u><u> </u><u>we </u><u>have </u><u>,</u>

  • Cylinder and cone
  • The height and diameter of the cylinder are 7m and 10m
  • Therefore , radius = 5 m

<u>We </u><u>know </u><u>that</u><u>, </u>

Curved Surface area of the cylinder

\sf{ = 2{\pi}rh}

<u>Subsitute the required values, </u>

\sf{ = 2{\times}3.14{\times}5{\times}7}

\sf{ = 6.28 {\times}5{\times}7}

\sf{ = 6.28 {\times}35}

\bold{ = 219.8m^{2}}

Thus, The area of the cylinder is 219.8m² .

<h3><u>Now</u><u>, </u></h3>

•We have to find the area of the cone.

•Here, Base of cone = diameter of the cylinder.

•The height of the cone will be

= Height of the tent - Height of cylinder

\sf{ = 19 - 7 }

\bold{ = 12 m }

<u>We </u><u>know </u><u>that</u><u>, </u>

Area of cone

\bold{ = {\pi}rl }

  • Here, l is the slant height.

Slant height of the cone

\sf{ = \sqrt{ h^{2} + r^{2}} }

\sf{ = \sqrt{ (12)^{2} + (5)^{2}} }

\sf{ = \sqrt{ 144 + 25}}

\sf{ = \sqrt{ 169}}

\sf{ = \sqrt{ 13{\times} 13 }}

\bold{ = 13 m }

Thus, The slant height of the cone is 13 m

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>

\sf{ = 3.14 {\times} 5 {\times} 13}

\sf{ = 3.14 {\times} 65}

\bold{ = 204.1 m^{2}}

Thus, The area of the cone is 204.1 m² .

<h3><u>Therefore</u><u> </u><u>,</u></h3>

The total area of the circus tent

\sf{ = 204.1 + 219.8}

\bold{ = 423.9m^{2} \: or \: 424 m^{2}}

<h3><u>Now</u><u>, </u></h3>

  • We have to find the total cost of making the tent.
  • The cost for 1 m² = 35

<u>Therefore</u><u>, </u>

The total cost for making the circus tent

\sf{ = 424 {\times} 35}

\bold{ = 14840}

Hence, The total cost for making the tent is 14840 .

7 0
2 years ago
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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title=" \frac{1}{2} " alt=" \frac{1}{2} " align=
BartSMP [9]
I hope this helps you 6x+2=7.2 6x+2=14 6x=12 x=2
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