Answer:
The possible numbers of songs that you can burn onto the CD is 11.
Step-by-step explanation:
The total storage capacity of CD = 70 minutes
Storage already used = 25 minutes
Hence, The available storage = Total available storage - Used Storage
= 70 minutes - 25 minutes = 45 minutes
Hence, the CD has 45 minutes storage left.
Now, each song takes up 4 minutes of storage.
⇒ 
= 
⇒The number of songs possible = 11.25 ≈ 11
Hence, the possible numbers of songs that you can burn onto the CD is 11.
Answer:
zono eatas
Step-by-step explanation:
elledre de como dezie puaron
Answer:
Step-by-step explanation:
Here's the formula for the volume of a right circular cylinder:
Here's what we are given and what we need to find:
Given that d = 10 cm, h = 20 cm, dd/dt = 1 cm/sec
Need to find dh/dt when V is constant
Since our formula has a radius in it and not a diameter but the info given is a diameter, we can use the substitution that
so
Now we can rewrite the formula in terms of diameter:
which simplifies down to
Now we will take the derivative of this equation with respect to time using the product rule. That derivative is
![\frac{dV}{dt}=\frac{\pi }{4}[d^2*\frac{dh}{dt}+2d\frac{dd}{dt}*h]](https://tex.z-dn.net/?f=%5Cfrac%7BdV%7D%7Bdt%7D%3D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%5Bd%5E2%2A%5Cfrac%7Bdh%7D%7Bdt%7D%2B2d%5Cfrac%7Bdd%7D%7Bdt%7D%2Ah%5D)
Now we can fill in our values. Keep in mind that if the volume is constant, there is no change in the volume, so dV/dt = 0.
![0=\frac{\pi }{4}[(100\frac{dh}{dt}+2(10)(1)(20)]](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B%5Cpi%20%7D%7B4%7D%5B%28100%5Cfrac%7Bdh%7D%7Bdt%7D%2B2%2810%29%281%29%2820%29%5D)
and
Multiply both sides by pi/4 to get
and solve for dh/dt:
Interpreted within the context of our problem, this means that the volume will be constant at those given values of diameter and height when the liquid in the cylinder is dropping at a rate of 4 cm/sec.
Answer:
I'm not guaranteeing this is the answer but 73.39% or 74%
Answer:
a. (3x² - 2x - 5) units²
b. (x² - x) units²
c. (2x² - x - 5) units²
Step-by-step explanation:
a. Area of the frame = L*W
L = (x + 1) units
W = (3x - 5) units
Area of the frame = (x + 1)(3x - 5)
Apply distributive property
x(3x - 5) +1(3x - 5)
3x² - 5x + 3x - 5
Area of the frame = (3x² - 2x - 5) units²
b. Area of the picture = L*W
L = x units
W = (x - 1) units
Area of the picture = x(x - 1)
Apply distributive property
= x² - x
Area of picture = (x² - x) units²
c. Area of the frame that surrounds the picture = area of frame - area of picture
= (3x² - 2x - 5) - (x² - x)
= 3x² - 2x - 5 - x² + x (distributive property)
Add like terms
= 3x² - x² - 2x + x - 5
= 2x² - x - 5
Area of the frame that surrounds the picture = (2x² - x - 5) units²
