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Vanyuwa [196]
3 years ago
14

Solve all values of x by factoring x^2-x-1=6x-1

Mathematics
1 answer:
sesenic [268]3 years ago
3 0

Answer:

x=0

x=7

Step-by-step explanation:

x²-x-1=6x-1

x²-x-1-6x+1=0

x²-7x=0

x(x-7)=0

x=0

x-7=0

x=7

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What is the slope of the line??
Semmy [17]

Answer:

sorry for being late  :/

Step-by-step explanation:

slope , m = 1/3  

3 0
3 years ago
In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 8 vowels and 12 consonants, what
velikii [3]

Answer: 6/25

Step-by-step explanation:

Number of vowels = 8

Number of consonants = 12

Total number of tiles in bag = (number of vowels + number of consonants)

Total = (12 + 8) = 20

Probability = (required outcomes / total possible outcome)

Probability of choosing a consonants = (number of consonants / total number of word tiles)

P( consonants) = 12 / 20 = 3/5

Since it is with replacement, total number of word tiles will still be 20

Probability of choosing a vowel = (number of vowels / total number of word tiles)

P( vowels) = 8 / 20 = 2/5

Therefore,

P(constant then vowel) = 3/5 * 2/5 = 6/25

4 0
3 years ago
What is the value of A when we rewrite 3.14^159x as A^x?
slavikrds [6]

The rule we'll use is

p^(q*r) = (p^q)^r

The exponents have been rearranged a bit.

In this case, p = 3.14, q = 159 and r = x, so,

p^(q*r) = (p^q)^r

3.14^(159*x) = (3.14^159)^x

This is in the form A^x with A = 3.14^159

3 0
3 years ago
A highway crossed a river that was 4.25 kilometers wide how wide is the river in decameters?
S_A_V [24]

Answer:

425 decameters

Step-by-step explanation:

1 kilometer is equal to one decameter

3 0
3 years ago
The base of a solid in the xy-plane is the first-quadrant region bounded y = x and y = x^2. Cross sections of the solid perpendi
musickatia [10]
Check the picture below.

thus, if one side on the square is x - x², then the area for the square is (x - x²)(x - x²), or (x - x²)²

now... what is the "x" value for the region, let's check their intersection.

\bf \begin{cases}
y=x\\
y=x^2
\end{cases}\implies x=x^2\implies 0=x^2-x\implies 0=x(x-1)
\\\\\\
x=
\begin{cases}
0\\
1
\end{cases}\\\\
-------------------------------\\\\
\displaystyle \int\limits_{0}^{1}\ (x-x^2)^2\cdot dx\implies \int\limits_{0}^{1}\ (x^2-2x^3+x^4)\cdot dx
\\\\\\
\cfrac{x^2}{2}-\cfrac{2x^4}{4}+\cfrac{x^5}{5}\implies \left. \cfrac{x^2}{2}-\cfrac{x^4}{2}+\cfrac{x^5}{5} \right]_{0}^{1}\implies \left[ \cfrac{1}{2}-\cfrac{1}{2}+\cfrac{1}{5} \right]-[0]\implies \cfrac{1}{5}

4 0
3 years ago
Read 2 more answers
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