3 years ago

What is the value of A when we rewrite 3.14^159x as A^x?

Mathematics

1 answer:

slavikrds [6]3 years ago

3 0

The rule we'll use is

p^(q*r) = (p^q)^r

The exponents have been rearranged a bit.

In this case, p = 3.14, q = 159 and r = x, so,

p^(q*r) = (p^q)^r

3.14^(159*x) = (3.14^159)^x

This is in the form A^x with A = 3.14^159

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