Answer:
Center: ( -1 , 2 )
Radius: 6
Step-by-step explanation:
The equation for a circle is given as follow:
Where,
the Center is: ( h , k ) (note that the signs of the number are different)
and the radius is: r
So if we compare the original circle equation to the equation in the question we can see that:
the Center is: (-1,2)
and the radius is: 
= 6
2. To draw the graph find points that lay on the circle, it's better to take the values of x and y from the Center:
first sub y=2 in the equation to find the values for x:
AND 
AND 
- The points are A(5,2) and B(-7,2)
second sub x= -1 in the equation to find the values for y:
AND 
AND 
- The points are D(-1,8) and E(-1,-4)
After finding the points write them in the graph and match them together to get the like the circle in the picture below:
Answer:
x=−5
Step-by-step explanation:
Steps:
Step 1 to 4 : Simplify
Steps 5: Calculating the Least Common Multiple
Steps 6: Calculating Multipliers
The correct answer for this question is x=−5
Answer: x=−5
<em><u>Hope this helps.</u></em>
It would be A because they’re both perfect squares
Let's assign variables for the unknowns. Let x be the amount of total sales while x is the amount of net sales. It is called net sales because a percentage is still deducted from it. The equation will be written as:
Net Sale = Total Sales - 0.25*Total Sales
y = x - 0.25x
y = 0.75x
he elements of the Klein <span>44</span>-group sitting inside <span><span>A4</span><span>A4</span></span> are precisely the identity, and all elements of <span><span>A4</span><span>A4</span></span>of the form <span><span>(ij)(kℓ)</span><span>(ij)(kℓ)</span></span> (the product of two disjoint transpositions).
Since conjugation in <span><span>Sn</span><span>Sn</span></span> (and therefore in <span><span>An</span><span>An</span></span>) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.
