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Degger [83]
3 years ago
10

There are 10 cards placed face down on a table. Four of the cards have stars on them and the other 6 are blank. You

Mathematics
1 answer:
stiv31 [10]3 years ago
4 0

The first one is out, because it isn't fair. We want a 50/50 chance to win. If we add 2 cards with stars, then your chance of winning increases too much(as much as that'd be great). If we take away 2 blank ones, it would be fair, but we want to still have 10 cards. So the only choice left is to add a start to 1 of the blank cards.

---

hope it helps

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In the triangle below,
Evgen [1.6K]

Answer:

x=8.6

Step-by-step explanation:

x=8.6

5 0
2 years ago
1) Billy walks 15 miles every day to soccer practice, and catches a ride home from his grandma. Billy had 5 practices last week.
nignag [31]

1 )  Billy walks 15 miles every day to soccer practice and he had 5 practices last week.

We know that,  1 mile = 1760 yards

So, 15 miles = (15× 1760) yards = 26400 yards

Thus the total distance walked in 5 practices will be: (26400*5)yards = 132000 yards


2) Mark's current age is t years

So, his age was in 10 years ago =(t-10)years

Given that, his current age is 3 times his age 10 years ago.

So, the equation to represent this situation will be :  t= 3(t-10)


3 0
3 years ago
Please help guys!!!!!!!!!!!!!!
hram777 [196]

Answer:

a) x = -10

b) x = 7

Step-by-step explanation:

a)

2(x + 3) = x - 4

2x + 6 = x - 4

2x - x = -4 - 6

x = -10

b)

4(5x - 2) = 2(9x + 3)

20x - 8 = 18x + 6

20x - 18x = 6 + 8

2x = 14

x = 7

7 0
2 years ago
Read 2 more answers
1/3 of a number T is less than or equal to five
ZanzabumX [31]

Answer: x ≤ 15

Step-by-step explanation: All we need to do is divide both sides by 1/3, so1/3x / 1/3 and 5/ 1/3 = 15. So x  ≤ 15.

Hope this helps!

8 0
3 years ago
Read 2 more answers
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
2 years ago
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