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ddd [48]
2 years ago
7

Rich bought 5 cupcakes and one pie. He knows his total bill is $13.14 and knows the pie was

Mathematics
1 answer:
Gre4nikov [31]2 years ago
3 0

$6.25

Take the total and subtract the amount of money from the pies to get the amount for cupcakes

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The Greens want to put an addition on their house 18 months from now. They will need to save $10,620 in order to achieve this go
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The answer is D because the additional 120 for the remaining six months only brings them to 9900. An additional month brings them to a total of 9690.
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4(3-x)=2(6-2x)<br> what is the answer to this equation
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Answer:

1

Step-by-step explanation:

12-4x=12-4x

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If HK = 4p - 51 and JK = p, find the value of p in parallelogram GHIJ,<br> help !
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Step-by-step explanation:

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Your friends and you notice a classmate who always has brand new clothes, shoes, and electronics. What would you need to know in
sashaice [31]

To know if the classmate’s family is actually wealthy, one will need to know their assets and their debt.

<h3>What is an asset?</h3>

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The asset should more than the debt.

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5 0
2 years ago
My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the
AVprozaik [17]

Answer:

a) n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

b) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.9=0.1 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

8 0
3 years ago
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