Answer:
The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.
Step-by-step explanation:
We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.
Let
= <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>
The z-score probability distribution for the sample mean is given by;
Z =
~ N(0,1)
where,
= population mean length of rods = 259.2 cm
= standard deviaton = 2.1 cm
n = sample of steel rods = 17
Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P(
> 259 cm)
P(
> 259 cm) = P(
>
) = P(Z > -0.39) = P(Z < 0.39)
= <u>0.65173</u>
The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.
The answer will be 1,2 you have to do 1/4 of the cords which are 4,8
When we say a statistic is resistant, we mean the extreme values do not affect the statistic to a large extent or to an extent which makes a major difference. Mean and median are example of such statistics. By changing the extreme values we do not see a substantial difference in the value of mean and median for the data set.
Consider a sample: 1,2,3,4,4,5,6,7,8
The median for this data set is 4.
If we change the extreme values to get this sample: -5,2,3,4,4,5,6,7,100
The median will still be the same i.e. 4. This is what is meant by a resistant statistic.
So option a is the correct ans.
Id have to say 5
Explanation: distributive property
Sorry if that’s wrong
-HOPE THAT HELPED!! <3
Answer:
3
Step-by-step explanation:
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