You want to find
P(1000 < X < 3000)
where X is normally distributed with mean 1751 and standard deviation 421. Transform X to Z, so that it follows the standard normal distribution with mean 0 and standard deviation 1 using the relation
X = 1751 + 421Z ==> Z = (X - 1751)/421
Then
P(1000 < X < 3000) = P((1000 - 1751)/421 < (X - 1751)/421 < (3000 - 1751)/421)
… ≈ P(-1.783 < Z < 2.967)
… ≈ P(Z < 2.967) - P(Z < -1.783)
… ≈ 0.9985 - 0.0373
… ≈ 0.9612
so that approximately 96.1% of the students fall in this income range.
Answer:
12.7 cm
Step-by-step explanation:
ABC
12² = 6² + BC²
12² - 6² = BC²
144 - 36 = 108
CB² = 108
√108 = 10.392
CB = 10.392
CBD
Sin (55°) = CB / CD
0.81915 = √108 / CD
CD = 10.392 / 0.81915
CD = 12.686
CD = 12.7cm
Answer:
17
Step-by-step explanation:
Evaluate the 2 expressions by substituting x = 2 , y = 3 into them
3x² - 2y
= 3(2)² - 2(3)
= 3(4) - 6
= 12 - 6
= 6
---------------------------
3y² - 2x
= 3(3)² - 2(2)
= 3(9) - 4
= 27 - 4
= 23
Then 23 - 6 = 17
Answer:
165,625 bags of cocoa.
Step-by-step explanation:
One trailer = 625 bags of cocoa, and if you have 265 trailers it means you will have to multiply 625 by 265.