Answer:
(2,4)
*View attached graph*
Step-by-step explanation:
2x + 3y = 16
2 + 2y = 10
2 + 2y = 10
-2 - 2
2y = 8
/2 /2
y = 4
2x + 3y = 16
2x + 3(4) = 16
2x + 12 = 16
- 12 - 12
2x = 4
/2 /2
x = 2
(x,y) -> (2,4)
Hope this helps!
Answer:
The proof is given below.
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
I feel like the answer is B. I hope this helped!
Answer:
x = - 12, y = - 9
Step-by-step explanation:
Given
- 4 + 3i - x + yi = 8 - 6i
Simplify left side by collecting like terms and equate like coefficients with the terms on the right side, that is
- 4 - x + i(3 + y) = 8 - 6i, thus
3 + y = - 6 ( subtract 3 from both sides ) ← equating imaginary parts
y = - 9, then
- 4 - x = 8 ( add 4 from both sides ) ← equating real parts
- x = 12 ( multiply both sides by - 1 )
x = - 12
Answer:
The result for an input of 7 is: 
The output (y-value) associated with an input of 3 is: 
Step-by-step explanation:
The image attached shown the graph for the rule
.
In order to use the graph to predict the result for an input value of 7, you need to follow these steps:
- Draw a vertical line from 
- When the vertical line touches the graph, you must draw a horizontal line to the y-axis to find the y-value.
You can observe in the graph that the result for an input value of
is 
Follow these steps in order to use the graph to predict the output value associated with an input value of 3:
- Draw a vertical line from 
- When the vertical line touches the graph, you must draw a horizontal line to the y-axis to find the y-value.
You can observe in the graph that the output value associated with an input value of
is 