To find the angles in these problems you have to do one of two things.
1) If we are looking for an interior angle with the exterior angle given, we can find the interior angle by subtracting the exterior angle from 180.
EX: Exterior angle K is 140. Therefore the interior angle is 40 (180 - 140 = 40).
2) If order to find an interior angle when you have other interior angles, add up the other interior angles and subtract them from 180.
EX) Interior angle A is 32 because the other angles are 120 and 28. (180 - 120 - 28 = 32)
ALSO, remember that the square is equal to 90 degrees. I've included an answer list for you below.
A = 32
B = 152
C = 65
D = 25
E = 37
F = 83
G = 97
H = 97
I = 83
J = 57
K = 40
L = 120
M = 60
N = 90
O = 79
P = 12
Answer:
1675 ft
Step-by-step explanation:
For us to calculate how close the windmill is to the fire, if we imagine it as a triangle, the distance from watch tower to the fire will be:
tan θ= opposite/adjacent
opposite=140 ft
adjacent = x
θ=3°
Thus;
tan 3 = 140/x
x=140/tan 3
x = 2,671.359 ft
Now, the distance from watch tower to windmill will be:
tan θ=opposite/ adjacent
θ=8°
opposite=140 ft
adjacent=y
thus
tan 8 = 140/y
y = 140/tan8
y=996.15 ft
Now, the distance between fire and wind mill will be:
x - y = 2671.359 - 996.15
x - y = 1675.209 ≈ 1675 ft
im not sure if you want the solution or interval notation. i'll put both
solution: -oo < x < oo
interval notation: (-oo, oo)
Answer:
f(g(5)) = 11
Step-by-step explanation:
- f(x) = x - 2
- g(x) = 3x - 2
The composite function f(g(5)) is found by plugging g(5) for x into f(x).
Let's find g(5) first.
- g(5) = 3(5) - 2
- g(5) = 15 - 2
- g(5) = 13
Next, plug this value for x into f(x).
- f(13) = (13) - 2
- f(13) = 11
∴ <u>f(g(5)) = 11</u>.
Answer:
n = 4
Step-by-step explanation:
![\sqrt[n]{256} = 8^{1/3} * 8^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7B256%7D%20%3D%208%5E%7B1%2F3%7D%20%20%2A%208%5E%7B1%2F3%7D)
![\sqrt[n]{256} = 8^{2/3}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7B256%7D%20%3D%208%5E%7B2%2F3%7D)
![\sqrt[n]{2^8} = 8^{2/3}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7B2%5E8%7D%20%3D%208%5E%7B2%2F3%7D)
< --- This is your answer
Hope this helps!
