Answer:
D. complementary
Step-by-step explanation:
If <1 and <4 combine, they cannot be supplementary because the 2 angles don't add up to 180*
<1 and <4 do not locate in the opposite parallel side -> not vertical
<1 and <4 do not locate next to each other -> not adjacent
Option B:
![$x=\pm 2\frac{1}{2}](https://tex.z-dn.net/?f=%24x%3D%5Cpm%202%5Cfrac%7B1%7D%7B2%7D)
Solution:
Given expression:
![$3 x^{2}=18 \frac{3}{4}](https://tex.z-dn.net/?f=%243%20x%5E%7B2%7D%3D18%20%5Cfrac%7B3%7D%7B4%7D)
To find the value of x:
![$3 x^{2}=18 \frac{3}{4}](https://tex.z-dn.net/?f=%243%20x%5E%7B2%7D%3D18%20%5Cfrac%7B3%7D%7B4%7D)
Convert mixed fraction into improper fraction.
![$3 x^{2}= \frac{18\times 4+3}{4}](https://tex.z-dn.net/?f=%243%20x%5E%7B2%7D%3D%20%5Cfrac%7B18%5Ctimes%204%2B3%7D%7B4%7D)
![$3 x^{2}= \frac{75}{4}](https://tex.z-dn.net/?f=%243%20x%5E%7B2%7D%3D%20%5Cfrac%7B75%7D%7B4%7D)
Divide by 3 on both sides of the equation, we get
![$x^{2}= \frac{25}{4}](https://tex.z-dn.net/?f=%24x%5E%7B2%7D%3D%20%5Cfrac%7B25%7D%7B4%7D)
![$ x^{2}= \frac{5^2}{2^2}](https://tex.z-dn.net/?f=%24%20x%5E%7B2%7D%3D%20%5Cfrac%7B5%5E2%7D%7B2%5E2%7D)
Taking square root on both side of the equation.
![$\sqrt{ x^{2}}= \sqrt{\frac{5^2}{2^2}}](https://tex.z-dn.net/?f=%24%5Csqrt%7B%20x%5E%7B2%7D%7D%3D%20%5Csqrt%7B%5Cfrac%7B5%5E2%7D%7B2%5E2%7D%7D)
![$ x=\pm \frac{5}{2}](https://tex.z-dn.net/?f=%24%20x%3D%5Cpm%20%5Cfrac%7B5%7D%7B2%7D)
Convert improper fraction into mixed fraction.
![$x=\pm 2\frac{1}{2}](https://tex.z-dn.net/?f=%24x%3D%5Cpm%202%5Cfrac%7B1%7D%7B2%7D)
Hence option B is the correct answer.
Answer:
D
Step-by-step explanation:
Answer:
hope it help PLZ MARK ME BRAINLIEST
-9+8k=7+4k
subtract 4k from both sides
-9+4k=7
add 9 to both sides
4k=16
divide both sides by 4
k=4