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3 years ago

Please please give answer for this question

Mathematics

2 answers:

Ahat [919]3 years ago

5 0

Answer:

each side of the hexagon measures 40 cm (which agrees with answer B)

Step-by-step explanation:

Recall that a regular hexagon has six equal sides, therefore, each side would be one sixth of the 240 cm:

each side of the hexagon = 240 cm / 6 = 40 cm

Novay_Z [31]3 years ago

5 0

Hexagons have 6 sides. 240 / 6 = 40 cm.

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What is the approximate value of x in the equation below.

fomenos

Answer: First Option

$x= -3.396$

Step-by-step explanation:

We have the following expression

$log_{\frac{3}{4}}25 = 3x -1$

To solve the equation add 1 to both sides of the equality

$log_{\frac{3}{4}}25 +1= 3x -1+1$

$log_{\frac{3}{4}}25 +1= 3x$

Divide between 3 to both sides of the equation

$\frac{log_{\frac{3}{4}}25 +1}{3}= x$

$x= \frac{-11.19 +1}{3}$

$x= -3.396$

The answer is the first option

3 0

4 years ago

Find the number of steel ball bearings, each of diameter 0.7 cm, that can be made from 1kg of steel, given that 1cm cubed of ste

liq [111]

Answer:

Ball Bearing Volume = (4 / 3) * PI * radius ^3

Volume = (4 / 3) * 3.14159265 * (.35)^3

Volume = (4 / 3) * 3.14159265 * 0.042875

Volume = 0.17959438 cc

1 cc of steel = 7.8 g

Volume of 1 kg of steel = 1,000 cc / 7.8 g per cc

1 kg = 128.205 cc

Number of ball bearings we can make = 128.205 / 0.17959438

Equals 713.86

Step-by-step explanation:

7 0

3 years ago

A train travels between two stations 1/2 mile apart in a minimum time of 41 sec. If the train accelerates and decelerates at 8 f

igomit [66]

It is important to notice firs of all that the train with no stop acceleration and them no stop acceleration would have a faster travel between stops. given this is safe to assume that there is a period during while the train is not accelerating nor decelerating. To find the time that is speed is constant
let's assume non-stop accelerating and decelerating and the time lost (subtraction of both) is the time the train had constant speed:

assuming same time accelerating a decelerating we have that the distance is

x = voT + 1/2aT^2 (initiial speed = 0) (0.25 miles = 1320 feets)
1320 = 1/2 (8)(T/2)^2
T/2 = 18.17 seg
T = 36.34 seg
time of constant speed
T = 41 -36.34 = 4.66 seg

maximum speed

v = v0 + aT (initial speed = 0)
v = 8(18.17) (time accelerating)
v = 145.36 feets/sec

distance at full speed

x = v*t
x = 145.36*4.66 = 677.38 feets

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4 years ago

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Calcule (1/2)-² POR FAVOR RESPONDEM

dolphi86 [110]

Answer:

I think it's 1/4 or .25

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3 years ago

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hoa [83]

Divisors of 18 are 1, 2, 3, 6, 9, 18.

Divisors of 24 are 1, 2, 3, 4, 6, 8, 12, 24.

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c) The number present must be a divisor of 6.

d) Possible numbers present are 1, 2, 3, 6.

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3 years ago

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