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3 years ago

9

Please help find volume of cone

1 answer:

Fudgin [204]3 years ago

5 0

Answer:

5275.2 m³

Step-by-step explanation:

We need the radius first:

$\sqrt{l^2- h^2}$ = 12

Formula for volume = πr²*h/3

Volume = 3.14 * 144 * 35/3

Volume = 5275.2

If my answer is incorrect, pls correct me!

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-Chetan K

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Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

3 years ago

At one point in time, a developing tissue of 200,000 cells has 800 cells in mitosis. What percent is this?

lyudmila [28]

Divided 200000 in half to get 100000 and the same to 800 then
change to percentages 4%
4% is the answer
thank me

7 0

3 years ago

Divide: 4/0 is it 0, undefined, 1, 4 or none of the above?

Gennadij [26K]

Answer: Undefined

Step-by-step explanation:

4/0 is undefined. This is because any number divided by zero is undifined.

7 0

3 years ago

Read 2 more answers

Please help, having a bit of trouble with it.

Dimas [21]

Answer:

.9b+2

Step-by-step explanation:

You first add 3.8b and -2.9b which equals .9b

Then you add -7 and 9 which equals 2

Hope this helped!

4 0

3 years ago

Can someone please help me with this question? Thank you!

Goryan [66]

Answer: A

<u>Step-by-step explanation:</u>

$\stackrel\frown{XY}$ ≅ $\stackrel\frown{YZ}$

⇒ ∠XOY ≅ ∠ZOY

$\overline{XO}$ ≅ $\overline{ZO}$ since they are both a radius

$\overline{OY}$ ≅ $\overline{OY}$ based on reflexive property

∴ ΔXOY ≅ ΔZOY by SAS

So, $\overline{XY}$ ≅ $\overline{ZY}$ by CPCTC

ZY = 10.2 is given

so, XY = 10.2 by substitution property

4 0

3 years ago