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3 years ago

I Need This One Also ASAP Plz Y= x2 - 2 =7

Mathematics

1 answer:

fredd [130]3 years ago

5 0

If that “ x” is suppose to be Multiplication then the answer is y=9/2

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Pls help quick 10 points

scZoUnD [109]

Answer:

6.86 to 2DP.

Step-by-step explanation:

7/12 = 4/DC

Cross multiply:

7DC = 4*12

DC = 48/7

= 6.857.

8 0

3 years ago

Read 2 more answers

To determine her power usage, Keri divides up her day into three parts: morning, afternoon, and evening. She then measures he

marusya05 [52]

Answer:

Stratified Sampling

Step-by-step explanation:

Since Keri divides the day into different strata and each unit is selected from each strata randomly. So, it is Stratified Sampling.

Further, In Stratified Sampling population is divided into several groups such that within the group it is homogeneous and between the group it is heterogeneous. And now a selection of each stratum and unit has an equal chance of selection.

3 0

3 years ago

A jungle has 594 birds.<br> It also has 62 snakes.<br> How many more birds than snakes are there?

vladimir1956 [14]

Answer:532

Step-by-step explanation:Do 594(birds)-62(snakes)=532

There are 532 more birds than snakes.

6 0

3 years ago

Read 2 more answers

In a video store, a DVD that sells for $15 is marked "10% off." What is the discount? What is the sale price of the DVD?

Margarita [4]

Answer:

it will be 1.50$ off as the discount so sold for 13.50 is the sale price

8 0

3 years ago

Read 2 more answers

If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal

lorasvet [3.4K]

Answer:

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability is $P(Z > 2.5 ) = 0.0062097$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 800$

The variance is $var(x) = 1600 \ kg$

The range consider is $x_1 = 778 \ kg \ x_2 = 834 \ kg$

The value consider in second question is $x = 900 \ kg$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{var (x)}$

substituting value

$\sigma = \sqrt{1600}$

$\sigma = 40$

The percentage of a cucumber give the crop amount between 778 and 834 kg is mathematically represented as

$P(x_1 < X < x_2 ) = P( \frac{x_1 - \mu }{\sigma} < \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma } )$

Generally $\frac{X - \mu }{ \sigma } = Z (standardized \ value \ of \ X)$

$P(x_1 < X < x_2 ) = P( \frac{778 - 800 }{40} < Z< \frac{834 - 800 }{40 } )$

$P(x_1 < X < x_2 ) = P(z_2 < 0.85) - P(z_1 < -0.55)$

From the z-table the value for $P(z_1 < 0.85) = 0.80234$

and $P(z_1 < -0.55) = 0.29116$

$P(x_1 < X < x_2 ) = 0.80234 - 0.29116$

$P(x_1 < X < x_2 ) = 0.51118$

The percentage is

$P(x_1 < X < x_2 ) = 51.1 \%$

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

$P(X > x ) = P(\frac{X - \mu }{\sigma } > \frac{x - \mu }{\sigma } )$

substituting values

$P(X > x ) = P( \frac{X - \mu }{\sigma } >\frac{900 - 800 }{40 } )$

$P(X > x ) = P(Z >2.5 )$

From the z-table the value for $P(Z > 2.5 ) = 0.0062097$

7 0

4 years ago