Do you mean 3y? If so, 3y = 1/2x + 2
3y - 1/2x = 2 is standard form
-2x + y = 8
y = 2x + 8
now sub in 2x + 8 for y in the other equation
3x + 2y = 2
3x + 2(2x + 8) = 2...distribute the 2 thru the parenthesis
3x + 4x + 16 = 2
7x = 2 - 16
7x = - 14
x = -14/7
x = -2
now sub -2 in for x in either equation to find y
-2x + y = 8
-2(-2) + y = 8
4 + y = 8
y = 8 - 4
y = 4
solution is : (-2,4)
<span>Three numbers can be defined as x, y, and z.
x + y + z = 64
y = x+3
z = 2x - 11
.
substitute for y and z
x + (x+3) + (2x-11) = 64
4x -8 = 64
4x = 72
x = 18
.
y = x+3 = 21
z = 2x -11 = 2(18) -11 = 36-11 = 25
.
x + y + z = 18 + 21 + 25 = 64
Correct.
.
Answer: The three numbers are 18, 21, and 25.</span>
Answer:
a.J+J+10=M
b. 15+10=25M
c. 9-10=-1 9+(-1)=8
Step-by-step explanation:
