A hyper-geometric distribution is used to define the probability distribution of k success in n samples drawn from a population of size N which include K success. Every draw is either a success of failure.

The random variable X = number of meals that will exceed the cost covered by the company.

The random variable X follows a hyper-geometric distribution.

The information provided is:

N = 15

K = 3

n = 5

k = 0

The probability mass function of a hyper-geometric distribution is:

$P(X=k)=\frac{{K\choose k}{N-K\choose n-k}}{{N\choose n}}$

Compute the probability that none of the meals will exceed the cost covered by your company as follows:

$P(X=0)=\frac{{3\choose 0}{15-3\choose 5-0}}{{15\choose 5}}=\frac{1\times 792}{3003}=0.2637$

Thus, the probability that none of the meals will exceed the cost covered by your company is 0.2637.

3 0

3 years ago

valkas [14]

Answer:

20 home runs left to hit.

Step-by-step explanation:

Ok so 100%/20% is 5. Increment 5 home runs until you get to 100%. So, 20% =5, 40% = 10, 80% = 15, and 100% = 20

7 0

3 years ago

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There were 94,172 people at a football on Saturday. On Monday, 1,000 fewer people were at a football game. In word form how many

Rzqust [24]

There was ninety three thousand one hundred seventy two people

7 0

2 years ago

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