All categories

3 years ago

Determine the intercepts of the line. 2.c + 5y = -6

Mathematics

1 answer:

CaHeK987 [17]3 years ago

5 0

Hello there,

The equation that is given to us is as follows:

2x + 5y = -6

Now we have to first put this equation in slope intercept form. So first we have to subtract 2x from both sides:

5y = -2x -6

Then we divide both sides by 5:

y = $-\frac{2}{5}$ x $-\frac{6}{5}$

Now that we have put the equation in slope-intercept form we should note that the number in front of the x is the slope and the other number is the y-intercept.

So the y-intercept of the following equation is $-\frac{6}{5}$ .

Hope I helped,

Amna

You might be interested in

PLEASE HELP LAST QUESTION

igomit [66]

ANSWER:

a) y = 15x + 75

b) 50 weeks

EXPLANATION:

P A R T A

2 weeks, 105 dollars --> (2, 105)

5 weeks, 150 dollars --> (5, 150)

if we use slope intercept form (y=mx+b), we must:

1) find the slope

y2 - y1 -->> 150 - 105 = 45

x2 - x1 -->> 5 - 2 = 3

45/3 = 15

2) find the y intercept

y = 15x + b -->> 150 = 15 (5) + b -->> 150 = 75 + b -->> 75 = b

--------------------------------------------------------------------------------------------

P A R T B

y = 15x + 75 (substitute the y with 825 because that is the goal)

825 = 15x + 75 (solve normally)

750 = 15x

50 = x

5 0

2 years ago

How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy

lisov135 [29]

Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

Mass of copper in $x$ pounds of that $15\%$ copper alloy: $(0.15\, x)\; \rm lb$ .
Mass of copper in $700$ pounds of that $30\%$ copper alloy: $700 \times 0.30 = 210\; \rm lb$ .