Answer:
I'm not entirely sure but I think that what is says is that it wants you to find the value of x in (4x+28) to make it 116 degrees because it is that same angle. So what you do is you get (4x+28)=116 and you do this because they are the same angle so you use 116 and get it to solve x. Since I'm lazy, then I go to this website and type the equation in: m a t h w a y . c o m but without all of the spaces, I had to do that so it would let me answer this, but I'll do it the real way this time. (4x+28)=116 Their is a rule in math that as long as you do something to one side of the equal sign in the equation, you have to do it to the other and it will still work. So, you minus 28 from both sides so that you can get rid of it and you now have 4x=88. Now you should know this part but you divide 4 from both sides to make so x is alone. Now you have x=22 because you divided 4 from each side. So their is your answer: x=22.
Step-by-step explanation: If you have the answer key that you can check from to make sure you got it right because I know some teachers let you do that, then you should make sure that is right, but I am pretty sure it is.
find three consecutive number whose sum shall equal 45
24 to the power of 4
24x10x10x10x10 = 240,000
If you thought this answer was helpful, please mark it as brainliest. I would greatly appreciate it!
I believe the first question is B:advertisement
I believe the second question is C: mass-media
I believe the third question is D: all of these are correct
I believe the fourth question is D: incentive
I believe the fifth question is A: it is free of bias
Hope this helps you have a great day!!!!!!
Answer:
S = {0,2,3,4}
P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001
Mean = 0.879
Standard Deviation = 1.033
Step-by-step explanation:
Let the number of people having same birth month be = x
The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)
The number of ways of distributing their birthdays = 12⁴
The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)
P(X = 0) = 
P(X=0) = 0.573
P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)
P(X=2) = 
P(X=2) = 0.401
P(X=3) = 
P(x=3) = 0.025
P(X=4) = 
P(X=4) = 0.001
Mean, 
Standard deviation, ![SD = \sqrt{\sum x^{2} P(x) - \mu^{2}} \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2} * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}](https://tex.z-dn.net/?f=SD%20%3D%20%5Csqrt%7B%5Csum%20x%5E%7B2%7D%20P%28x%29%20-%20%5Cmu%5E%7B2%7D%7D%20%20%5C%5CSD%20%3D%5Csqrt%7B%20%5B%20%280%5E%7B2%7D%20%2A%200.573%29%20%2B%20%282%5E%7B2%7D%20%20%2A%200.401%29%20%2B%20%283%5E%7B2%7D%20%2A%200.025%29%20%2B%20%284%5E%7B2%7D%20%2A%200.001%29%5D%20-%200.879%5E%7B2%7D%7D)
SD = 1.033
