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goblinko [34]
4 years ago
11

Write an equation for the line passing through the points (-5,15) and (20,25). Show how you found your answer.

Mathematics
1 answer:
olasank [31]4 years ago
7 0

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-5, 15) and (20, 25). substitute:

m=\dfrac{25-15}{20-(-5)}=\dfrac{10}{25}=\dfrac{2}{5}\\\\y-15=\dfrac{2}{5}(x-(-5))\\\\y-15=\dfrac{2}{5}(x+5)\qquad|\text{use distributive property}\\\\y-15=\dfrac{2}{5}x+2\qquad|\text{add 15 from both sides}\\\\y=\dfrac{2}{5}x+17\qquad|\text{multiply both sides by 5}\\\\5y=2x+85\qquad|\text{subtract 2x from both sides}\\\\-2x+5y=85\qquad|\text{change the signs}\\\\2x-5y=-85

Answer:

point-slope form: y-15=\dfrac{2}{5}(x+5)

slope-intercept form: y=\dfrac{2}{5}x+17

standard form: 2x-5y=-85

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Complete question

To find \sqrt{5} , Beau found 2^2 = 4 and 3^2 = 9 . He said that since 5 is between 4 and 9, \sqrt{5}, is between 2 and 3. Beau thinks a good estimate for \sqrt{5} , is \frac{2 + 3}{2} =  2.5 Is his estimate high or low? How do you know?

Answer:

The estimation is high because 5 is very close to 4 so \sqrt{5} will also be very close to \sqrt{4} which is lower than the estimate

In order to get a good estimate

The first step is to choose a number between 2 and 3 let say 2.8 , 2,85 , 2.9 and the square them

i.e

2.1^2 =  4.41

     2.2^2 =  4.84

      2.3^2 =  5.29

From here we can see that \sqrt{5}  lies between 2.2 and 2.3 but is closer to  2.2

So a good estimate for \sqrt{5} is 2.2

Step-by-step explanation:

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