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maxonik [38]
3 years ago
6

A rectangular pool has a width of 24 feet. A second rectangular pool has a perimeter of 48 feet, which

Mathematics
1 answer:
Alina [70]3 years ago
5 0

Answer:

Let x = the length

Let P = the perimeter of the first pool

48 = (1/3)P

144 feet = P

P = 2l + 2w

144 = 2x + 2(24)

144 = 2x + 48

96 = 2x

48 feet = x

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3 years ago
Use a table to find the solution to the situation.
AysviL [449]

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Find the area of the region bounded by the curves y= sin^-1(x/6), y=0, and x=6 obtained by integrating with respect to y. Your w
Ahat [919]
Check the picture below.

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\begin{cases}
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\end{cases}\\\\
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\bf -------------------------------\\\\
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4 years ago
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Monica [59]

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3 0
4 years ago
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Sonja [21]

Answer:

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