<span>Cone Volume = (<span>π<span> • r² •<span> h) ÷ 3
Original cone = (3.14 * 6^2 * 12) / 3
</span></span></span></span>
<span><span>Original cone = 452.16
</span>
cc
</span>Larger cone = <span>(3.14 * 6^2 * 18) / 3 = </span>
<span>
<span>
<span>
678.24
</span>
</span>
</span>
cc
Difference = <span>(678.24 -452.16) = </span>
<span>
<span>
<span>
226.08
</span>
</span>
</span>
cc
A) f(x) is decreasing because the base is less than 1.
0.56 is close to 0.5, so its like saying that you are taking half each time, therefore the value is getting smaller.
g(x) is increasing because the base is greater than 1.
you are multiplying by 4 each time, making the value bigger.
B ) The y-intercept is where x=0.
Anything to the '0' power is 1. Therefore the y-intercept is equal to the coefficient in front of each function.
f(x) = 3 , g(x) = 6
C) Just plug in x=4 to each function in a calculator.
f(4) = 0.295
g(4) = 1536
Answer:
- g(- x) = - 70 - 3x
Step-by-step explanation:
to evaluate g(- x) substitute x = - x into g(x)
g(- x) = 70 - 3(- x) = 70 + 3x, hence
- g(- x) = - (70 + 3x) = - 70 - 3x
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
#SPJ1
Answer:
13 means the starting number
13 is the y-intercept (0,13)
