Answer:
1)28.8%
2)28.8%
3)43.6%
Step-by-step explanation:
1))Probability of wining both = Probability that first contract is won* Probability that second contract is won = 0.4 * 0.72 = 0.288 = 28.8%
2)Probability of losing = 1 - Probability of winning
Probability that they will lose both contracts = Probability that first contract is lost * Probability that second contract is lost = (1 - 40/100) * (1 - 54/100) = 0.276 = 27.6%
3)Probability that any one is won = 1 - both contracts are won - both contracts are lost = 1 - 0.276 - 0.288 = 0.436 = 43.6%
Y = mx+b
m= 4
y= 4x+b
solve for b using (6,-1)
-1 = 4 (-1)+b
b=3
therefore equation is y=4x+3
same as (y+1)=4(x-6)
Answer:
23.76
Step-by-step explanation:
Answer:
I think 4:1 I'm not that sure tho
<span>5x-6y=-15
5x+6y=12
---------------add
10x = -3
x = -3/10
x = -0.3
</span>5x+6y=12
5(-0.3) + 6y = 12
6y = 12 + 1.5
6y = 13.5
y = 13.5 / 6
y = 2.25
