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miskamm [114]
3 years ago
8

Help help help help helpA=√18-√8+√50Write A in the form m√2 where m is an integer​

Mathematics
2 answers:
butalik [34]3 years ago
8 0

Answer:

6√2

Step-by-step explanation:

A=3√2-2√2+5√2

A=6√2

sergij07 [2.7K]3 years ago
4 0

Answer:

6√2

Step-by-step explanation:

A=√18-√8+√50 = √9√2 - √4√2 + √2√25, or A = (√2)(3 - 2 + 5) = 6√2

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Mega Movies hosted a film premiere on Friday night. They charged $8 for adults and $4 for children. One hundred eight adults and
Zanzabum

Answer:

B.

Step-by-step explanation:

14 x 4 + 137 x 8 = $1,152

hope this helps

have a great day

and a Merry Christmas UwU

3 0
3 years ago
There are Z fish in a aquarium. 1/4 of the fish are angelfish. How may are angelfish?
blsea [12.9K]

Step-by-step explanation:

since there are z fishes

the number of angelfish = <u>1</u><u> </u> × z

4

= <u>1</u><u> </u>z

4

7 0
2 years ago
Read 2 more answers
Write a cosine function that has a midline of 2, an amplitude of 4 and a period of pi/2.
exis [7]

y = Acos(Bx) + D;

D = 4, A = 2. Now T = 2π/B = 5π/8, B = 2π/(5π/8) = 16/5

WE get y = 2cos(16/5x) + 4

4 0
2 years ago
How to write y-6=-5/2 (x+4)
coldgirl [10]

Answer:

In point slope form, this is y = (-5/2)x + 2.  In standard form, it's (5/2)x + y = 2.

Step-by-step explanation:

y-6=-5/2 (x+4) has already been written in point-slope form.  The slope of the line is -5/2 and the point on the line is (-4,6).

In slope-intercept form:  add 6 to both sides of the original equation, obtaining y = 6 - (5/2)(x + 4), or y = 2 - (5/2)x, or y = (-5/2)x + 2


8 0
3 years ago
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 20%
zhuklara [117]

Answer:

a. 5% of the employees will experience lost-time accidents in both years

b. 24% of the employees will suffer at least one lost-time accident over the two-year period

Step-by-step explanation:

a. What percentage of the employees will experience lost-time accidents in both years?

20% last year, of those who suffered last year, 25% during this year. So

p = 0.2*0.25 = 0.05

5% of the employees will experience lost-time accidents in both years.

b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?

5% during the two years.

10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.

So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.

First year yes, not on the second.

75% of 20%. So, total:

0.05 + 0.05*0.8 + 0.75*0.2 = 0.24

24% of the employees will suffer at least one lost-time accident over the two-year period

3 0
3 years ago
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