FIND VALUE OF SLOPE PLEASE

Which equation could match the table?

DochEvi [55]

Answer:

y=2x+3

Step-by-step explanation:

in third line x = 0 y=2×0+3 =3

5 0

2 years ago

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What is the following product? Sqr5x^8y^2 sqr10x^3 sqr12y

PSYCHO15rus [73]

Step-by-step explanation:

$\sqrt{5 {x}^{8} {y}^{2} } \times \sqrt{10 {x}^{3} } \times \sqrt{12y} \\ \\ = {x}^{4} y \sqrt{5} \times x \sqrt{10x} \times 2 \sqrt{3y} \\ \\ = 2 {x}^{5} y \sqrt{5 \times 10x \times 3y} \\ \\ = 2 {x}^{5} y \sqrt{5 \times 5 \times 2x \times 3y} \\ \\ = 2 {x}^{5} y \times 5\sqrt{ 2x \times 3y} \\ \\ = 10 {x}^{5} y \sqrt{6xy} \\$

4 0

3 years ago

Which part is which from the circle

gizmo_the_mogwai [7]

<h3>Check out the diagram below for the proper labeling</h3>

The radius goes from the center to the edge of the circle.

The diameter is twice as long as the radius; it is a segment going through the center with both endpoints on the circle

The circumference is the distance around the circle. Think of it as the perimeter of the circle.

3 0

2 years ago

A friend has a 82% average before the final exam for a course. That score includes everything but the final, which counts for 30

Damm [24]

So you want to set up an equation for a weighted average. You know the final is 30% of the grade, so everything else is 70%. This gives you:

(Final)(.30) + (other grades)(.70) = course grade

The best grade the student can get would be if they get a hundred on the final, since that’s the best score you can make on the final. Then,

(100)(.30) + (82)(.70) = course grade
30 + 57.4 = course grade = 87.4 Which, If you round, the student would get an 87.

For the last part, we use the same equation, just filling in different parts.

(Final)(.30) + (other grades)(.70) = course grade

This time, we don’t know the grade for the final, but we know the course grade.

(Final)(.30) + (82)(.70) = 75
(Final)(.30) + 57.4 = 75
(Final)(.30) = 17.6
Final = (17.6)/(.30)
Final = 58.667 Which is approx a 59.

4 0

3 years ago

A road is made in such a way that the center of the road is higher off the ground than the sides of the road, in order to allow

Jet001 [13]

Remark.

The problem is a bit indistinct. Where exactly are the two edges of the road? I'm going to say that they are the x intercepts, but that may not be true. Certainly it does not have to be true at all.

Graph.

A graph has been made for you. The maximum is marked for you. It is an approximation The actual height can be more accurately found.

Height

y = (-1/200)(x - 16)(x + 16)

y = (-1/200)*(x^2 - 256)

The maximum height for this graph only is when x = 0.Other graphs require completing the square.

y = (-1/200) * (-256)

y = 1.28 exactly. I thought the graph might be rounding the answer. It is not.

4 0

3 years ago

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