The answer is y = -3x + 4
Answer=140 fish
200 gallons of water in the first aquarium.
200 gallons of water in the second aquarium.
The first will be for the small fishes.
5 small fish x fish
_____________=__________
10 gallons 200 gallons
cross multiply
10x=1000
divide both sides by 10
x=100 small fish
The first aquarium has 100 small fish.
The second aquarium holds large fish.
8 large fish x fish
____________=___________
40 gallons 200 gallons
cross multiply
40x=1600
divide both sides by 40
x=40 large fish
The second aquarium has 40 large fish.
100small fish+40 large fish=140 total fish
Answer:
A=m-n-p
Step-by-step explanation:
So solve for a, we have to isolate it on one side, so -a=n+p-m. So a=m-n-p
The answers are
M1 = 112°
M2 = 26°