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DENIUS [597]
3 years ago
5

IS THIS CORRECT ?? HELP ASAP THANKS!

Mathematics
1 answer:
OLEGan [10]3 years ago
3 0

Pretty sure it is.......

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A golf lesson lasts from 10:00am -11:15 and includes a 15 min break with equal lengths of time before and after the break. At wh
mel-nik [20]

Answer:

10:30am

Step-by-step explanation:

total lesson time is 1 hr and 15 min (10 to 11:15).

lesson time is 1 hr total and the break mid way is :15 long.

the lesson before the break is from 10-10:30 (:30 length)

break is at 10:30 (:15 long concluding at 10:45).

lesson resumes at 10:45 when break is over

the lesson runs another :30 until 11:15 (10:45-11:15)

halfway thru the lesson is 10:30am for the break to start

8 0
3 years ago
a pool only open when the temperature is at least 72 degrees. Which inequality represents the temperature t, when the pool is op
BartSMP [9]

Answer:

t ≥ 72

Step-by-step explanation:

The pool has to be at least 72° or MORE to open, so we are going to have a greater sign with an equal sign under indicating that the temperature has to  at least be 72° or be greater than 72°. (≥)

5 0
2 years ago
Please help me fast I need to finish this before 8:00!!!!!!
TiliK225 [7]

Answer:

Yes

Step-by-step explanation:

Hard to explain

6 0
2 years ago
The sum of 2 numbers is 9 and the difference is 5
melamori03 [73]

Answer:

The numbers are 2 and 7.

Step-by-step explanation:

If x and y are the 2 numbers:

x + y = 9

x - y = 5       Adding the 2 equations

2x + 0 = 14

x = 7.

Plug this into the first equation:

7 + y = 9

y = 2.

4 0
3 years ago
Read 2 more answers
The quadratic formula works whether the coefficients of the equation are real or complex. Solve the following equations using th
RoseWind [281]

Answer:

z=i+2

,

z=i-2

Step-by-step explanation:

Remember that the quadratic equation az^2+bz+c=0 has the complex solutions z=\frac{-b\pm \sqrt{b^2-4ac}}{2a} (this is the quadratic formula).

Apply this with a=1, b=-2i and c=-5 to get:

z=\frac{2i\pm \sqrt{(-2i)^2-4(-5)}}{2}=\frac{2i\pm \sqrt{-4+20}}{2}=\frac{2i\pm 4}{2}. Then the solutions are

z_1=\frac{2i+4}{2}=i+2 and z_1=\frac{2i-4}{2}=i-2

It isn't necessary to use De Moivre's formula.  

6 0
3 years ago
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