Hello:
<span>Use De Moivre’s Theorem :
</span>(3(cos27 +isin27)^5 = 3^5( cos(27 × 5) +isin(27 × 5))
= 3^5 ( cos(135)+i sin(135))
= 3^5(-√2/2+i √2/2)
because : cos(135) = -√2/2 and sin(135) = √2/2
(3(cos27 +isin27)^5 = (- 3^5√2/2)+ i ( 3^5√2/2) ...(form : a+ib when
a= (- 3^5√2/2) and b = ( 3^5√2/2)
1 hour and 10 minutes = 70 total minutes
The aerobics class is 20 minutes and then since the yoga class is 30 minutes longer it will then be 50 minutes.
20 minutes aerobic+50 minutes yoga= 70 total minutes
I will help you on two conditions: 1) that you never again call yourself "stupid," and that you ask no more than 1 or 2 questions per post.
I'll focus on #5. Recall that distance = rate times time: d = r*t.
You want distance and are given rate and time: rate 1.8 km/min; time 48 min.
I see you write "distance" next to "1.8 km;" that is not correct, because
the problem states that "the rate is 1.8 km per minute." 1.8 km is a distance; 1.8 km / min is not (it's a rate).
So, again, to find the distance traveled, mult. the rate by the elapsed time:
distance = (1.8 km/min)(48 min) = 86.4 km, or about 54 miles.
ITS IS 8x-7y-5z=15 I THINK'
I am the diffrence of the two numbers... sum is 36 so the larger is double the size of the smaller the only numbers that work are 24 and 12 so the diffrence would be 12
