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3 years ago

Pls i really need this 20 points I will give brainliest

Mathematics

1 answer:

zubka84 [21]3 years ago

4 0

Answer:

Step-by-step explanation:

I hope this helps!

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in a recipe for double chocolate every 1/2 cup of milk calls for 2 cups of chocolate. if the recipe were increased to include 4

luda_lava [24]

Milk : chocolate
1/2 : 2
(x2) (x2)
1 : 4

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Answer : You will need 1 cup of milk for 4 cups of chocolates.
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4 0

3 years ago

Read 2 more answers

Please help me.......

7nadin3 [17]

<u>Answer:</u>

Point Q lies on the circumference of the circle.

<u>Step-by-step explanation:</u>

We are given a circle with the point C (4,3) as its center with a radius of 3.16 units and we need to figure which of the given point lies on the circumference of the circle.

We can find this by using the distance formula:

Distance between C and P = $\sqrt{(4-2)^2+(3-1)^2} = \sqrt{8} = 2.82$

Distance between C and Q = $\sqrt{(4-7)^2+(3-4)^2} = \sqrt{10} = 3.16$

Distance between C and R = $\sqrt{(4-1)^2+(3-3)^2} = \sqrt{9} = 3$

Since the distance between the points C and Q equals to the radius of the circle, therefore point Q lies on the circumference of the circle.

7 0

3 years ago

Find the 22nd term in the arithmetic sequence -5, -9, -13, -17, -21

lubasha [3.4K]

Answer:

-93

Step-by-step explanation:

it decreases by four every time, so take -4 times 22 and then subtract 5.

4 0

3 years ago

Determine the measure of the indicated angle (in degrees).

ohaa [14]

Answer:

105°

Step-by-step explanation:

Same-side interior angles are supplementary, so angle 4 and the one marked 75° are supplementary.

∠4 = 180° -75°

∠4 = 105°

4 0

3 years ago

Prove the following identity showing all steps:

kiruha [24]

Answer:

See solution below

Step-by-step explanation:

Given the expression

$\frac{cos(x+30)-sin(x+60)}{sin(x)cos(x)} \\$

Recall that

cos x = sin(90-x)

cos(x+30 ) = sin (90-(x+30)

= sin(90-x-30)

= sin(60-x)

Substitute

$\frac{sin(60-x)-sin(x+60)}{sin(x)cos(x)} \\= \frac{sin60cosx-cos60sinx)-sinxcos60-cosxsin60)}{sin(x)cos(x)} \\= \frac{-2cos60sinx)}{sin(x)cos(x)} \\= \frac{-2(1/2)sinx)}{sin(x)cos(x)} \\= \frac{-1}{cos(x)}\\= \frac{1}{cos(x)}\\ \\= -sec(x) Proved$

8 0

3 years ago