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motikmotik
3 years ago
12

Given you select a female, what probability will they prefer playing NBA2K20? Round your answer to the nearest thousandth. _____

_____A. 0.609 B. 0.463 C. 0.185 D.0.398

Mathematics
1 answer:
Marina86 [1]3 years ago
8 0

Answer:

B

Step-by-step explanation:

just divide 152 by 328 and youll get 0.463

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(7)/((12)/(.14))=(50x)/(4.8)
umka2103 [35]

Answer:

x=0.00784

Step-by-step explanation:

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2 years ago
Factor as the product of two binomials.<br> 22 + 11x + 18
Dahasolnce [82]

Answer:

11x +40

Step-by-step explanation:

Add 22 and 18 and the result will be as above.

4 0
3 years ago
100000000000005654 divided by 8
fgiga [73]

Answer:

1.25E16

Step-by-step explanation: calculator

5 0
3 years ago
What is the domain of the function graphed below?
WITCHER [35]

From the graph, the domain of the function will be {x| x = −2,1}. Then the correct option is D.

<h3>What is an asymptote?</h3>

An asymptote is a line that constantly reaches a given curve but does not touch at an infinite distance.

From the graph, the domain of the function will be

The function is not defined for x = 2 and x = -1.

Then the domain will be

{x| x = −2,1}

Then the correct option is D.

More about the asymptote link is given below.

brainly.com/question/17767511

#SPJ1

5 0
2 years ago
Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ&gt;0
eduard
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2787701

_______________


\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\&#10;\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\&#10;\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}


Square both sides:

\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\&#10;\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\&#10;\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\&#10;\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}

\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\&#10;\mathsf{17\,sin^2\,\theta=1}\\\\&#10;\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\&#10;\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}


Since \mathsf{sin\,\theta} is positive, you can discard the negative sign. So,

\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}


Substitute this value back into \mathsf{(i)} to find \mathsf{cos\,\theta:}

\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\&#10;\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0
3 years ago
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