Answer:
0.0649350649350649
Step-by-step explanation:
Answer:
78.46
Step-by-step explanation:
Given that
Pop. Standard deviation = 1.61
Sample standard deviation = 2.15
Sample mean = 7.47
Sample size = 45
Recall that
Test stat for chi square
= (n - 1) (sample standard dev/pop standard dev)^2
= 45 - 1 (2.15/1.61)^2
= 44(1.3354)^2
= 44 × 1.78329
= 78.46
F: R -> R, f(x) = ax + b;
f(1) = 8 => a + b = 8;
f(2) = 14 => 2a + b = 14 => a = 6 and b =2;
f(3) = 20 => 6*3 + 2 = 20 True;
f(4) = 26 => 4*6 + 2 = 26 True;
then, f:R -> R, f(x) = 6x + 2;
Answer:
b. There's no statistically significant linear relationship between the number of miles driven and the maintenance cost
Step-by-step explanation:
The p-value for the slope estimate show us how strong is the certainty that there are a linear relationship between both variables. In this case, the p-value for the slopes shows if there is a significant relationship between the number of miles driven and the maintenance cost.
If we have a high p-value like 0.7 we can said that there is no certainty in the linear relationship. it means that there's no statistically significant linear relationship between the number of miles driven and the maintenance cost.
