Answer:
4.11% probability that he has lung disease given that he does not smoke
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Does not smoke
Event B: Lung disease
Lung Disease/Nonsmoker 0.03
This means that 
Lung Disease/Nonsmoker 0.03
No Lung Disease/Nonsmoker 0.7
This means that 
What is the probability of the following event: He has lung disease given that he does not smoke?
4.11% probability that he has lung disease given that he does not smoke
1/6(36 + 1/2) = 6 + 1/12 = 72/12 + 1/12 = 73/12
Hopes this helps:
Answer: 48
<span>1.) In numbers from 1 to 12, there are 4 numbers that are divisible by 3 (3,6,9 and 12), meaning there will be 4 possible outcomes if a number will be drawn from 12 numbers. The probability of drawing a number divisible by 3 is 4/12 or 1/3.
2.) In the movie drawer, there are 15 movies, seven are action movies, five comedies, and three dramas. The probability of choosing an action movie is 7/15, while a comedy is 5/15. The probability of choosing an action or a comedy is higher at (7/15+5/15) or 12/15 equivalent to 4/5.
3.) Having drawn 8 black marbles and 2 white marbles from a bag of 100 marbles give a probability of 8/10 (4/5) for black marbles and 2/10 (1/5) for white marbles. If there are 100 marbles, we can predict that there are 4/5(100) equivalent to 80 marbles in the bag.</span>
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4.) On a youth soccer team, three out of 12 team members have played in previous years. Based on this information, if 180 kids are in the youth soccer league, then the number of members who could be expected to have played the year before is 3/12 or ¼ of 180 which is 45. </span>
