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Oksi-84 [34.3K]
2 years ago
12

Which describes the correlation shown in the scatterplot?

Mathematics
2 answers:
kolezko [41]2 years ago
8 0

Answer:

C. There is no positive or negative correlation.

Step-by-step explanation:

as you can see, it is straight up and down :))

enot [183]2 years ago
7 0

Answer:

C.There is no positive or negative correlation.

Step-by-step explanation:

finished Unit Test and got it correct

You might be interested in
Farmer bob's square plot ofland is slowly eroding away. Worried about the future of his farm. Farmer Bob measures the rate of er
kow [346]

Answer:

Option A.

Step-by-step explanation:

Area of a square is

A=x^2               .... (1)

where, x is side length.

The length of each side of his square plot is decreasing at the constant rate of 2 feet/year.

\dfrac{dx}{dt}=2

It is given that bob currently owns 250,000 square feet of land.

Fist find the length of each side.

A=250000

x^2=250000

Taking square root on both sides.

x=500

Differentiate with respect to t.

\dfrac{dA}{dt}=2x\dfrac{dx}{dt}

Substitute x=500 and \frac{dx}{dt}=2 in the above equation.

\dfrac{dA}{dt}=2(500)(2)

\dfrac{dA}{dt}=2000

Farmer bob is losing 2,000 square feet of land per year.

Therefore, the correct option is A.

7 0
2 years ago
un rectangulo tiene 28 cm de perimetro y unos de sus lados mide 4 cm ¿cuantos cuadrados de 2 cm por lado se mecesitan para armar
seraphim [82]

Answer:

10 cuadrados

Step-by-step explanation:

Si uno de los lados de rectangulo es de 4cm entonces el lado parallelo tambien es de 4cm. Eso nos da 8cm del perimetro y nos quedan los otros dos lados que tienen la misma medida. Entonces dividimos el resto del perimetro por 2.

28 - 8 = 20cm

20cm / 2cm = 10cm

Ahora que tenemos todas las medidas podemos multiplicar el largo por el ancho para calcular el area del rectangulo

10cm * 4cm = 40cm^{2}

el cuadrado de 2cm tendra un area de

2cm * 2cm = 4cm^{2}

Ahora simplemente dividimos el area del rectangulo por el area del cuadrado para saber cuantos cuadrados necesitamos para armar ese rectangulo

40cm^{2} / 4cm^{2} = 10 cuadrados

3 0
2 years ago
What is 10 4/5 minus 3 1/2
Oksanka [162]
The answer is 7.3 or in other words 7 3/10

Hope I helped
4 0
3 years ago
Read 2 more answers
What is the solution of the system? Use elimination. 7x + 5y = 19 −7x − 2y = −16
netineya [11]

Make the coefficient of y the same in both equations:

To do this, multiply equation one by 2, and equation two by 5 (this will make the coefficient 10 in both).

14x + 10y = 38
-35x - 10y = -80


Eliminate the y variable by adding the equations from each other

   (14x + 10y = 38)
+ (-35x - 10y = -80)
=  -21x +  0y  = -42

We now have -21x = -42. The y variable has been eliminated.


Solve for x

-21x = -42

Divide both sides by -21 to get x on its own.

x = 2


Substitute x into the equation to find y.

7*2+5y=19

14+5y=19

Subtract 14 from both sides.

5y=19-14

5y=5

Divide by 5 on both sides to get y on its own.

y=5/5

y=1


The answer is (2,1)


8 0
3 years ago
The strength of a certain type of rubber is tested by subjecting pieces of the rubber to an abrasion test. For the rubber to be
My name is Ann [436]

Answer:

Step-by-step explanation:

Hello!

You have the hypothesis that the average weight loss for rubber after an abrasion test is less than 3.5 mg. To test this a large sample of pieces of rubber were sampled and subjected to the abrasion test.

With the given information you must test whether the researcher's hypothesis is sustained or not.

The study variable is,

X: Weight loss of rubber cured in a certain way after being subjected to the abrasion test. (mg)

There is no information about the variable distribution, but since it is said that the sample is a "large number" I'll take it as if it is bigger than 30 and apply the Central Limit Theorem to use the approximation of the sample mean to normal. This way I can use the Z-statistic for the test.

Symbolically the statistic hypothesis is:

H₀: μ ≥ 3.5

H₁: μ < 3.5

α: 0.05 (since is not listed, I'll choose one of the most common signification levels)

You have a one-tailed critical region, this means the p-value will also be one-tailed to the left of the distribution (i.e. →-∞)

The formula of the statistic is:

Z= <u> X[bar] - μ </u> ≈ N(0;1)

        δ/√n

To calculate the statistic you have to use the information given.

The sample mean X[bar]= 3.4 mg

Upper bond of 95% CI= 3.45 mg

The basic structure of a CI for the mean is

"estimator" ± "margin of error"

Upper bound is "estimator" + "margin of error"

Using the formula:

Ub= X[bar] + d ⇒ 3.45= 3.4 + d

⇒ d= 3.45 - 3.4 = 0.05

Where d is the margin of error

d= Z_{1-\alpha /2} * (δ/√n)

d= Z_{0.975} * (δ/√n)

d/Z_{0.975}= (δ/√n)

(δ/√n)= 0.05/ 1.96 = 0.0255

(δ/√n) is the denominator in the formula, corresponds to the standard deviation of the distribution.

Now you have all values and can calculate the statistic under the null hypothesis:

Z= <u> 3.4 - 3.5 </u> = -3.92

       0.0255

And the p-value:

P(Z ≤ -3.92) = 0.000044 ⇒ My Z- table goes up to P(Z ≤ -3.00) = 0.001, so using strictly the table I can say that the probability is less than 0.001.

To calculate the exact probability I've used a statistic program.

p-value < 0.001

I hope it helps!

8 0
3 years ago
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