Answer:
2.33 Seconds
Step-by-step explanation:
The equation y = -6t^2 - 10t + 56 expresses the height of a ball at a given time, t, on the planet Mars. We are also given that the ball is thrown with a velocity of 10 feet per second with the initial height of 56 feet.
To find the amount of time to reach the ground, we can say that the time being found will be when the ball is on the ground, or when y = 0. So we simply set our equation to 0 and solve for t.
y = -6t^2 - 10t + 56
0 = -6t^2 - 10t + 56
0 = -1 (6t^2 + 10t + -56)
0 = -1 (3t - 7) (2t + 8)
(3t - 7) = 0 OR (2t + 8) = 0
3t = 7 OR 2t = -8
t = 7/3 OR t = -4
Since time will not be negative, we will want to choose the positive solution for this quadratic equation.
Hence, the amount of time for the ball to hit the ground will be 7/3 seconds or 2.33 seconds.
Cheers.
Answer:
7^22
Step-by-step explanation
Given the expression
7^8 × 7^3 × 7^4 × 7^7
In indices
a^m × a^n = a^{m+n}
The powers are added since the base are the same
We ate going to add all the powers of the expression given since they have the same base which is 7
7^8 × 7^3 × 7^4 × 7^7
= 7^{8+3+4+7}
= 7^22
= 3.91×10^18
Answer:
b. One in Five
Step-by-step explanation:
To calculate probability, we need to know the formula: 
in this case the probability is given in its decimal form, which is = 0.20
∴ to be able to use our formula easily, we will need to convert the probability to its fraction form.
which is 0.20 =
(<em> to do this, just simply put a 1 under the decimal point and replace the remaining values of 20 with zeroes)</em>
reducing
to its simplest form gives
.
Hence, relating it to our formula, we can see that the number of possible out comes is = 1
and the total number of outcomes = 5.
This means that the probability that the order will execute before the same of closing is the same as 1 in 5
Answer:
25x^2 - 4
Step-by-step explanation:
and x times an x is x^2 so
25x^2 - 4
Answer:
none of these
Step-by-step explanation:
3.2 would equal 30 because replace it
4.5 would equal 40
6.4 would equl 60
7.6 would eqaul 70
I could be wrong but this was how i was taught