HELLO,
I am not sure but I think its this
2y5 • (xy70 + y2<span> + 2)
HOPE THIS HELPS U AND GOODLUCK:) </span>
Answer:
1.-t₁ = 0,625 s
2.-h(max) = 6,25 f
3.-t = 1,25 s
Step-by-step explanation:
V₀ = 20 f/s
h(t) = - 16*t² + 20*t
h(max) = ??
h´(t) = - 32*t + 20
h(max) will occurs when V = 0 dh/dt = 0 then
- 32*t + 20 = 0
- 32*t = -20
t = 20/32
t₁ = 0,625 s
h(max) = h(0,625) = - 16*(0,625)² + 20*0,625
h(max) = - 6,25 + 12,5
h(max) = 6,25 f
c) The ball will hit the ground
t = 2*t₁
t = 2*0,625
t = 1,25 s
Answer:
Domain = 0≤m≤20 for mEZ+
Range = $100≤A≤$700 for all values of m
Step-by-step explanation:
Initial amount in the account = $100
Amount saved by beth monthly = $30
Amount in the bank after X month = $100+$30X where X is the number of months beth intend to save up to.
The amount in her bank in her first month = $100+$30(1)
= $100+$30
= $130
Amount saved in the second month will be when X = 2
= $100+$30(2)
= $100+$60
= $160
The amount in the bank will keep increasing by $30 monthly until the 20month.
The amount he will have in her bank in the 20th month will be at when X = 20
= $100+30X
= $100+30(20)
= $100+$600
= $700
This means that her money will be $130 in the first month and will keep increasing until it reaches $700 in the 20th month.
The DOMAIN will be the interval of the time she used in saving. Since she saved for 20months, the domain will be expressed as 0≤m≤20 for mEZ+ where m is the number of month she uses to save.
The Range will represent the amount she saved within the specified time and will be expressed as $100≤A≤$700 for all values of m.
Where $100 is the amount in the account initially and $700 is the amount in the account after 20 months.
From the attached graphic, Half-life = ln (.5) / k
Half-life =.693147 / <span>0.1142
= </span><span><span><span>6.0695884413
</span>
days
The value of "k" should be negative and should have units associated with it.
</span>
</span>
Answer:
its 34
Step-by-step explanation:
