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Nuetrik [128]
3 years ago
11

HELP!! ILL GIVE BRAINLESS Comparing Functions: Mastery Test

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
4 0
I think the answer is D not to sure
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A concrete mix is designed to withstand 3000 pounds per square inch​ (psi) of pressure. The following data represent the strengt
ss7ja [257]

Answer:

Mean = 3640

Mode = 4100

Median = 3830.

Step-by-step explanation:

We are given the following data in the question:

Strength of casts (in psi):

3970,4100,3100,3200,2950,3830,4100,4050,3460

Formula:

Mean = \displaystyle\frac{\text{Sum of all observation}}{\text{Total number of observations}}

\displaystyle\frac{3970+4100+3100+ 3200+ 2950+ 3830+4100+ 4050+ 3460}{9} = \displaystyle\frac{32760} {9} = 3640

Mode is the entry with most frequency. Thus, for the given sample mode = 4100.

Median

Since n = 9 is odd,

Formula:

Median = \displaystyle\frac{n+1}{2}th~term

Data in ascending order:

2950,3100,3200,3460,3830,3970,4050,4100,4100

Median = 5th term = 3830.

7 0
4 years ago
Amelia had 26 sea shells. Then, she collected 11 more sea shells. After that, she gave S sea shells to her little sister. Which
Makovka662 [10]

Answer:

C. 26 + 11 - S

Step-by-step explanation:

She had 26 shells

She collected 11 more shells ( that is addition)

26 + 11

Then she gave S shells away ( that is subtraction)

26+11-S

She has 26+11-S

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4 years ago
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Can someone plz help me quickly!! First to answer will be marked brainliest!
Anton [14]

Answer:

128 cookies in 8 hours

Step-by-step explanation:

3 0
3 years ago
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Only answer if you’re sure, will give Brainly :) thank you
nadezda [96]
The answer is 44 h(-7)= -7^2 -5 =49-5=44
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3 years ago
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Write the equation in slope intercept form of the perpendicular bisector of a segment with endpoints of (2,5) and (4.9). ​
m_a_m_a [10]
The slope from (2,5) to (4,9) is 4/2 or just 2.
A perpendicular will have a gradient of -1/2
The midpoint is (3,7)
Therefore y=mx+c becomes 7=-1/2 x 3 + c
c = 7 + 3/2
The perpendicular bisector has the equation y = -1/2x + 17/2
4 0
3 years ago
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