Two events are occurring:
1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3
Probability of getting an odd number = 3/6
2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2
The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12
Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario.
So correct answer is option C
Answer:
Step-by-step explanation:
nani
I think it is 0.9 I think
Answer:
initial value is 21
Step-by-step explanation:
y=mx+b
6= -3(5) +b
b=21
Answer:
pizza parlor to ferris wheel
pizza parlor to bumper cars
Step-by-step explanation:
