Area of right-angled triangle is given by;
Area, A = 1/2 *b*h, Where b=base, h=height
Therefore,
A1 = 1/2bh = 16 in^2
A2 = 1/2 (2b)(2h) = 2bh
Ratio of increase = A2/A1 = {2bh}/(1/2bh} = 4 (the area is increased 4 times)
The,
A2 = 4*16 = 64 in^2
Therefore,
The area is increased by (64-16) = 48 in^2
A system of equations is good for a problem like this.
Let x be the number of student tickets sold
Let y be the number of adult tickets sold
x + y = 200
2x + 3y = 490
x = 200 - y
2(200 - y) + 3y = 490
400 - 2y + 3y = 490
400 + y = 490
y = 90
The number of adult tickets sold was 90.
x + 90 = 200 --> x = 110
2x + 3(90) = 490 --> 2x + 270 = 490 --> 2x = 220 --> x = 110
The number student tickets sold was 110.
Answer:
Volume of prop = 706.5 in³
Step-by-step explanation:
Given:
Radius = 5 in
Height = 17 in
Find:
Volume of prop
Computation:
Volume of prop = Volume of cone + Volume of hemi-sphere
Volume of prop = 1/3(π)(r²)(h) + 2/3(π)(r)³
Volume of prop = 1/3(3.14)(5²)(17) + 2/3(3.14)(5)³
Volume of prop = 444.83 + 261.67
Volume of prop = 706.5 in³
The lateral surface area is the surface area of the cube excluding the base and the top, which would make 4 square planes.
First we can find the area of a square plane:
4 1/2 x 4 1//2
=20 1/4 ft²
We can then multiply the area of plane by 4:
20 1/4 x 4
=81 ft²
Therefore the answer is 81 ft².
Hope it helps!
