The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>
The given parameters are:
Perimeter = 210 meters
Let the length parallel to the wall be represented as z and the width be x
So, the perimeter of the fence is
P = 2x + z
This gives
210 = 2x + z
Make x the subject
x = 1/2(210 - z)
The area of the wall is calculated as
A = xz
So, we have
A = 1/2(210 - z) * z
This gives
A = z/2(210 - z)
Rewrite as
A(z) = z/2(210 - z)
Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
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Let's call the width: w
the lenght is then 3w+4 ("4 more than 3 times the width")
and the parameter would be 2(w+3w+4), that is 2*(4w+4), that is 8w+8.
this is also equal to 18.4:
8w+8=18.4
8w=10.4
w=1.3
this is the width, and the lenght is:
4+3*1,3=4+3.9=7.9
and the area is their product:
1.3*7.9=10.27
Answer:(Fog)(-6)=29
Step-by-step explanation:
(fog)=-3(2x+2)-1
=-6x-6-1
=-6x-7
(fog)(-6)= -6(-6)-7
=36-7
=29
Answer:
Plane: C) A flat surface that extends infinitively and has no depth; it has length and width
Perpendicular Lines: B) Two lines that intersect at 90° angles
Parallel Lines: E) Two lines that lie within the same plane and never intersect
Circle: D) A set of all points in a plane that are given distance from a plane
Angle: A) A figure consisting of two rays with a common endpoint
I hope this helps
this is 100% correct
plz mark me brainliest
