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Ket [755]
3 years ago
8

TRUE or FALSE: Billy is paid $32 for 8 hours of work. He gets peid $4 per hour

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0

Answer:

True

Step-by-step explanation:

We know Billy is paid $32 for 8 hours of work.

All we have to do is divide 32 by 8 to see if whether he gets paid 4 dollars an hour,

32/8

==> 4

This is true

You might be interested in
Please help me it is easy<br> I just dont understand
postnew [5]

Answer:

13%

15%

41%

31%

Step-by-step explanation:

To find the percentage one amount is out of another amount, divide the smaller amount by the bigger amount. You will end up with a decimal (0.xy where x is the 10% place and y is the 1% place).

For example: to find the percentage that 39 is out of 300 students, we divide 39 by 300. This gives us the decimal 0.13. Written as a percentage, that is 13%.

We can do this for all of them.

Here is the math for each one:

39 ÷ 300 = 0.13 → 13%

45 ÷ 300 = 0.15 → 15%

123 ÷ 300 = 0.41 → 41%

93 ÷ 300 = 0.31 → 31%

Once you have all these decimals, you might choose to check your work by adding them up. They should at up to 1.00, or 100%. In this case, they do, so we know these answers are correct.

I hope this helps. Please let me know if you have questions.

4 0
1 year ago
What is the value of n when 7n-13=5n+7
anyanavicka [17]
7n-13=5n+7
7n-5n=7+13
2n=20
n=20/2
n=10
7 0
3 years ago
Read 2 more answers
Dorothy wrapped 2 presents in 4 minutes. At that rate, how many
madam [21]

Answer:

90

Step-by-step explanation:

2 presents per 4 minutes is 30 presents per hour multiplied by 6 hours is 90 presents

5 0
2 years ago
Describe the image D first reflected across line I then across line m.
AleksAgata [21]

Answer:

Please check the <em>attached figure</em> to determine the new orientation of image D after first reflecting across line l and then across line m.

Step-by-step explanation:

<em>Describe the image D first reflected across line I then across line m.</em>

In mathematics, a reflection can be termed as just a "flipping" or an "overturn "of an object over a certain axis or line - commonly known as the line of reflection - without altering the shape and size of the original object, though facing in opposite directions.  

<em />

<em>First Step: </em>

After the first reflection of letter D across the line l, it would again be a letter D. But the letter D would be a "turned D" letter, though having the same size but locating itself to the right side of the line l as shown in figure. The letter "Turned D" will have its curved side facing the left.

Hence, after the first reflection of letter D across the line l, the "turned D" will have its curved side facing the left, would be having same size but locating to the right side of the line l and also having located to the left side of line m as shown in figure.

<em>Second Step: </em>

After the second reflection across the line m, it would again convert, flip or overturn the the letter to the original object or letter, and its curved side again facing the right (original shape) , but now it would be locating itself to the right side of the line m as shown in figure.

So, new orientation of the image D is attached below.

Keywords:  reflection, reflection across line

Learn more about reflection from brainly.com/question/9590916

#learnwithBrainly

6 0
3 years ago
What does the fundamental theorem of algebra state about the equation 2x^2−6x+10=0 ?
Temka [501]

Answer:

B. The fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. The roots are ​ x=3±i√11/2 .  

Step-by-step explanation:

We know that,

Fundamental theorem of algebra states that ' a polynomial of degree n will have n number of roots'.

Since, the polynomial y=2x^{2}-6x+10 has degree 2, so it will have 2 roots.

We know that the polynomial ax^{2}+bx+c=0 has roots given by x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}.

So, the roots of polynomial 2x^{2}-6x+10=0 will be,

x=\frac{6 \pm \sqrt{(-6)^{2}-4 \times 2 \times 10}}{2 \times 2}

i.e. x=\frac{6 \pm \sqrt{36-80}}{4}

i.e. x=\frac{6 \pm \sqrt{-44}}{4}

i.e. x=\frac{6 \pm 2i \sqrt{11}}{4}

i.e. x=3 \pm \frac{\sqrt{11}i}{2}

Hence, the roots are given by 3 \pm \frac{\sqrt{11}i}{2}

So, option B is correct.

5 0
3 years ago
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