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Dmitry_Shevchenko [17]
2 years ago
6

Explain how to solve the equation 21 = m +14. What is the value of m?

Mathematics
2 answers:
Katyanochek1 [597]2 years ago
6 0

Answer:

m = 7

Step-by-step explanation:

21 = m + 14

21 - 14 = m

m = 7

sdas [7]2 years ago
4 0

Answer:

21=m+14

21-14=m+14-14

7=m

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Euleuy VI, Ulalla PUSIUI 407220)
Artyom0805 [142]

Answer:

Using the Angle Addition Postulate, 20 + m∠DBC = 80. So, m∠DBC = 60° using the subtraction property of equality.

Step-by-step explanation:

If point D is the interior of angle ABC, then the angle addition postulate theory states that the sum of angle ABD and angle DBC is equals to angle ABC. The angle addition postulate is used to measure the resulting angle from two angles placed side by side.

From the attached image, ∠ABD and ∠DBC are placed side by side to form ∠ABC. Given that m∠ABD = 20° and m∠ABC = 80°

Hence, using angle addition postulate:

m∠ABD + m∠DBC = m∠ABC

20 + m∠DBC = 80

subtracting 20 from both sides (subtraction property of equality)

m∠DBC = 80 - 20

m∠DBC = 60°

3 0
2 years ago
Chitra has 8 4/5 room
ycow [4]

Answer:

She can paint 4 rooms.

Step-by-step explanation:

8\dfrac{4}{5} \div 2\dfrac{1}{5}=\dfrac{(8\times 5+4) \times 5}{5 \times (2\times 5 + 1)}=\dfrac{44}{11}=4

8 0
3 years ago
Find the length of the curve given by ~r(t) = 1 2 cos(t 2 )~i + 1 2 sin(t 2 ) ~j + 2 5 t 5/2 ~k between t = 0 and t = 1. Simplif
xxMikexx [17]

Answer:

The length of the curve is

L ≈ 0.59501

Step-by-step explanation:

The length of a curve on an interval a ≤ t ≤ b is given as

L = Integral from a to b of √[(x')² + (y' )² + (z')²]

Where x' = dx/dt

y' = dy/dt

z' = dz/dt

Given the function r(t) = (1/2)cos(t²)i + (1/2)sin(t²)j + (2/5)t^(5/2)

We can write

x = (1/2)cos(t²)

y = (1/2)sin(t²)

z = (2/5)t^(5/2)

x' = -tsin(t²)

y' = tcos(t²)

z' = t^(3/2)

(x')² + (y')² + (z')² = [-tsin(t²)]² + [tcos(t²)]² + [t^(3/2)]²

= t²(-sin²(t²) + cos²(t²) + 1 )

................................................

But cos²(t²) + sin²(t²) = 1

=> cos²(t²) = 1 - sin²(t²)

................................................

So, we have

(x')² + (y')² + (z')² = t²[2cos²(t²)]

√[(x')² + (y')² + (z')²] = √[2t²cos²(t²)]

= (√2)tcos(t²)

Now,

L = integral of (√2)tcos(t²) from 0 to 1

= (1/√2)sin(t²) from 0 to 1

= (1/√2)[sin(1) - sin(0)]

= (1/√2)sin(1)

≈ 0.59501

8 0
3 years ago
A survey of several 8 to 9 year olds recorded the following amounts spent on a trip to the mall: $31.11,$25.01,$18.53,$14.37,$24
Alex17521 [72]

Solution :

Amounts spent on a trip : $31.11, $25.01, $18.53, $14.37, $24.16, $21.91

Confidence interval = 80%

Average amount spent = 8 to 9 years old

One sample T confidence interval

μ : Mean of variance

80% of confidence interval results :

Using statistical software,

Variable : data

Sample mean : 22.515

Std. Err. = 2.3479945

DF = 5

L. limit : 19.049632

U. Limit : 25.980368

SD = 5.75

Critical value = 1.476

8 0
3 years ago
Polly's veterinarian told her a dog that weighs w kilograms needs 30w+70 calories each day to stay healthy. Polly's dog, Otis, w
Crank
Since w is 22, you substitute w with 22. 30(22) + 70 equals 730 calories
7 0
3 years ago
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