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2 years ago

HELPPPPPPPPPPPPPPPPPPPPPP PWESEEEEEEEEEEEEEEEE

Mathematics

2 answers:

belka [17]2 years ago

8 0

Answer: D. The experimental probability is greater than the theoretical probability.

Step-by-step explanation:

Experimental Probability

Sam rolled a 6 39/75 times

39/72 = 0.52 probability

Theoretical Probability

The likelihood of rolling a 6, in general, is 1/6, as a die has 6 sides, and a 6 is found on one of the six sides.

1/6 = 0.167 probability

52% experimental > 16.7% probability, thus the answer would be D.

kirill [66]2 years ago

7 0

Answer:a or possibly c

Step-by-step explanation:

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PLS HELP, I'm not very good at math so I need the answer to this

statuscvo [17]

Answer:

A BT = CT

Step-by-step explanation:

BAT ≅ CAT

That means

The angles are the same and the sides are the same by CPCTC

AB = AC

CT = BT

AT=AT

and

< BAT = <CAT

< ATB = <ATC

< TBA = <TCA

Given the choices on the left

A BT = CT is one of them

4 0

2 years ago

I need help with this real quick

Leni [432]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

(08.03)

Alik [6]

Answer:

Option D, (x + 2)(x - 6)

Step-by-step explanation:

<u>Step 1: Factor </u>

x^2 - 4x - 12

x^2 - 6x + 2x - 12

(x - 6)(x + 2)

(x + 2)(x - 6)

Answer: Option D, (x + 2)(x - 6)

8 0

2 years ago

find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.

DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}$

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}$

Or, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}$

Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 × $\frac{171}{4}$

∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0

3 years ago

How do I solve this problem

CaHeK987 [17]

Use cymath it gives you the answer :)

6 0

2 years ago