Answer:
Refer below
Step-by-step explanation:
a) a and b are the lower and higher values of the interval for which uniform distribution is defined.
Here a= 6 and b =10
b) Mean of the uniform distribution= (a+b)/2 = (6+10)/2 =8
Or int x (1/4) dx = x^2/8 = 8
c) Variance of the uniform distribution = (b^2-a^2)/12 = (100-64)/12
= 36/12 =3
Std dev = sq rt of 3 = 1.732
d) To find total area
PDF of the distribution = 1/(b-a) = 1/4, 6<x<10
Area = \int 6 to 10 of 1/4 dx
= x/4
Subtitute limits
= (10-6)/4 =1
So total area = 1
d)P(X>7) = int 7 to 10 of 1/4 dx = 3/4
e) P(7<x<9) = Int 7 to 9 of 1/4 dx = 2/4 = 1/2
Answer:
i would say B/90
Step-by-step explanation:
First subtract the original high from the new high:
567 - 540 = 27 more vacuums sold.
Now divide the increase amount by the original high and multiply that by 100 to get the percentage:
27 / 540 = 0.05
0.05 * 100 = 5% Increase.
Here are two ways of doing it.
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1) The current price is 100% of the price. The price went down by 6%, so since 100% - 6% = 94%, the new price is 94% of the original price.
94% * 175 = 0.94 * 175 = 164.50
The new price is 164.50
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2) The discount is 6% of 175, so first, we find the discount.
6% of 175 = 0.06 * 175 = 10.5
Now we subtract the amount of the discount from the original price.
175 - 10.50 = 164.50
The new price is 164.50
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As you can see, both methods give you the same answer, 164.50