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mr Goodwill [35]
3 years ago
7

For what value of x is line a parallel to line b?

Mathematics
2 answers:
Yuliya22 [10]3 years ago
6 0
The correct answer is  x=20
<span>Enter 20 in the  box</span>
5x+15=1155x=100x=20
and to check (5x +15) = 115 are corresponding angles(5)(20)+15 Substitute x for 20=115
galben [10]3 years ago
4 0
Check the picture below.

now, if those two angles are corresponding, that means they're equal, therefore then

5x + 15 = 115

and surely you know what "x" is, and for that value, the angles are corresponding and therefore the lines are parallel.

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A rectangular playground has a perimeter of 180 feet. If the width of the playground is 24 feet less than the length, what is th
Blababa [14]
P = 2(L + W)
P = 180
W = L - 24
now we sub
180 = 2(L + L - 24)
180 = 2(2L - 24)
180 = 4L - 48
180 + 48 = 4L
228 = 4L
228/4 = L
57 = L

W = L - 24
W = 57 - 24
W = 33

so ur length (L) = 57 ft and ur width (W) = 33 ft
3 0
3 years ago
/forms/d/e/1FAIpQLSed EhBHljwHakF6vZWŁYYZG6BSihvt7EL1HPBZJYDL_IP9-Jw/formResponse
Elza [17]

Answer:

A

Step-by-step explanation:

Im not sure if the answer is correct tho

3 0
3 years ago
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The markup is changed to 34% ;how does the expression for the retail price change?
malfutka [58]
If wholesale cost is x, then retail is x plus the percentage change in x. (1 + .34)x = 1.34x.
8 0
3 years ago
X-45=8(2x+3)-18 what are the first steps to solving this equation
Mamont248 [21]

Step-by-step explanation:

step one Distribute

x−45=8(2x+3)−18

x−45=16x+24−18

step two Subtract the numbers

x−45=16x+24−18

x−45=16x+24−18

3 0
3 years ago
3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
KiRa [710]

Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

6 0
2 years ago
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