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SIZIF [17.4K]
2 years ago
15

5 scholars ran a marthon each one ran 1\5 of a mile how far did the students run in all

Mathematics
1 answer:
IrinaK [193]2 years ago
3 0

9514 1404 393

Answer:

  1 mile

Step-by-step explanation:

  5 × (1/5 mi) = 5/5 mi = 1 mi

The students ran 1 mile in all.

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“the product of a number and 3 is the same as the sum of that number and sione half of a number is 8 less than the number itself
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Answer:

USE GOOGLE BEFORE COMING HERE

Step-by-step explanation:

7 0
3 years ago
If y=3x and 2x−4y=3 , then x=
tatiyna

Answer:

x = -3/10

Step-by-step explanation:

Solve for x by substituting y = 3x into the other equation:

2x - 4y = 3

2x - 4(3x) = 3

Simplify and solve for x:

2x - 12x = 3

-10x = 3

x = -3/10

So, x = -3/10

3 0
2 years ago
Read 2 more answers
A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.
mezya [45]
1. Divide wire b in parts x and b-x. 

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= \frac{1}{2}sin60^{o}side*side=   \frac{1}{2} \frac{ \sqrt{3} }{2}  (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}
A=\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2}  )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

 2 \pi r=x

so r= \frac{x}{2 \pi }

Area of circle = \pi  r^{2}= \pi  ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2}  }* x^{2} = \frac{1}{4 \pi } x^{2}

4. Let f(x)=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)=\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b

x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

6. So one part is \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) } and the other part is b-\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

4 0
3 years ago
Read 2 more answers
Vicki is 5 years older than twice Ella's age, a.
Anettt [7]

Answer:

5+3a=29

Step-by-step explanation:

let Ella's age be 'a'

Vicki's age=5+2a

sum of their ages= 29

So, the equation is

  (5+2a)+a=29

       5+3a=29

<em>hope this helps!</em>

8 0
3 years ago
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Mr Bartley is taking the theater club
PtichkaEL [24]
What is he doing behind stage
8 0
3 years ago
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