A(-4,5)
B(-3,1)
C(-5,2)
A rotated(3,1)
B rotated(2,5)
C rotated(4,4)
        
                    
             
        
        
        
Answer:
2√5
Step-by-step explanation:
Using the formula for calculating resultant
R = √Fx + Fy
\sum Fx = -2sin 45 + 4 cos 45
\sum Fx =  2cos45
\sum Fx = 2(1/√2)
\sum Fx   = 2/√2
Similarly;
\sum Fy = 2 cos 45 + 4 sin45
\sum Fx  = 2(1/√2) + 4(1/√2)
\sum Fx = 6/√2
Magnitude = √(2/√2)²+6/√2)²
Magnitude = √4/2 + 36/2
Magnitude = √2+18
Magnitude = √20
Magnitude = 2√5
Hence the magnitude of their sum is 2√5
 
        
                    
             
        
        
        
Answer:
See attached 
Step-by-step explanation:
Refer to picture
 
        
             
        
        
        
The answer to this questions is letter B
        
                    
             
        
        
        
Answer:
he area that is un-shaded is (x-3)(x-6). 
 
The entire area is (2x+2)(3x-4).
 
 
Area of the shaded region is:
 
(2x+2)(3x-4) - (x-3)(x-6) =
 
(6x2-2x-8) - (x2-9x+18) =
 
6x2-2x-8-x2+9x-18 =
 
5x2+7x-26 hopes this help btw (;