Question

Consider a single-line, single-server waiting line system. Suppose that customers arrive according to a Poisson distribution at an average rate of 60 per hour, and the average (exponentially distributed) service time is 45 seconds per customer. What is the probability that there are no customers in the system?
A 15%
B 20%
c 25%
D 30%
E 35%

Answer 1

Answer:

Correct answer is C i.e 25%

Explanation:

Arrival rate = λ = 60 / hour

Service Rate = μ = (60 * 60) / 45 = 80 / hour

Probability of no customers in the system = Po = 1 - λ/μ = 1 - 60/80 = 0.25 or 25%