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sp2606 [1]
3 years ago
15

The histogram displays the tree growth in one year for a sample of trees measured at Shady Farms.

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
4 0

Answer:

1.48 2.100

Step-by-step explanation:

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1.write the equations of three lines whose graphs are parallel to one another . 2.write the equation of two lines whose graphs a
Arlecino [84]
Y = -2x + 1
y = -2x + 2
y = -2x + 3
these are all parallel lines because they have the same slopes (-2) but different y intercepts.

y = 3x + 4
y = -1/3x + 3
these are perpendicular lines because they have negative reciprocal slopes.

slope of a line parallel to the x axis : If it is parallel to the x axis, it is a horizontal line and has a slope of 0.

slope of a line perpendicular to the x axis : if it is perpendicular to the x axis, it is a vertical line with a slope that is undefined.

slope of line parallel to the y axis : vertical line, undefined slope

slope of a line perpendicular to the y axis : horizontal line, slope of 0


6 0
4 years ago
Read 2 more answers
You want to purchase a new car in 5 years and you anticipate the cost of the car to be $55,000. You are given an investment plan
Usimov [2.4K]
Wow - that is an unusual calculation.  You'll need a formula for the monthly payment of a monthly annuity, and it is located here:
http://www.1728.org/annuity3.htm  (see formula 2)
You'll find THAT page and THIS page very helpful:
http://www.1728.org/annuitym.htm


rate = rate / 1,200
rate = <span> <span> <span> 0.005166666667 </span> </span> </span>
n= number of months = 5 * 12 = 60

monthly amount = [Total] / ([(1 + rate)^(n+1) -1] / [rate]) -1

monthly amount =
55,000 / [[( 1<span>.005166666667)^</span>(61)-1] /  1<span>.005166666667] -1
</span>
monthly amount = 55,000 / [[<span><span>1.3693761617</span> -1</span>] / .005166666667]-1
monthly amount = 55,000 / [[.3693761617] / .005166666667]-1
monthly amount = 55,000 / ((<span> <span> <span> 71.4921603244)-1)
</span></span></span>monthly amount = 55,000 / (<span> <span> 70.4921603244)</span></span>
<span><span><span>monthly amount = 780.2286062293 </span> </span> </span>
OR 780.23 (rounded)

Yes, it's just that "simple". LOL


5 0
4 years ago
Read 2 more answers
When 2x^2 - 20x + 49 = 19 is written in the form (x - p)^2 = q, what is the value of q?
9966 [12]

Answer: 10

Step-by-step explanation:

5 0
3 years ago
F(-2) = -1 and g(1) = -2<br> (Fog)(1)
yulyashka [42]

The value of the composite function fog(1) is -1

Step-by-step explanation:

Step 1 :

Given,

 f(-2) = -1

g(1) = -2

We need to find (fog)(1)

Step 2 :

Function f(2) means the value of the function f when x = 2

fog refers to composite function f(g(x)), that is evaluate the function g for x and then evaluate the function f for the result

So to find the composite function (fog)(1) we need to find g(1) first and then apply the function f on the result.

so g(1) = -2

f(g(1))=f(-2) = -1

fog(1) = -1

Step 3 :

Answer :

The value of the composite function is -1

7 0
3 years ago
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean 1263 and a stan
DENIUS [597]

Answer:

(a) The 29th percentile for the number of chocolate chips in a bag is 1198.65.

(b) The number of chocolate chips in a bag that make up the middle 95​% of bags are [1146, 1380].

(c) The inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies is 157.83.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of chocolate chips in a bag of chocolate chip cookies.

The random variable <em>X</em> is normally distributed with mean, <em>μ </em>= 1263 and a standard deviation, <em>σ </em>= 117.

(a)

Compute the 29th percentile for the number of chocolate chips in a bag as follows:

P (X < x) = 0.29

⇒ P (Z < z) = 0.29

The value of <em>z</em> for the above probability is, <em>z</em> = -0.55.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sogma}\\-0.55=\frac{x-1263}{117}\\x=1263-(117\times 0.55)\\x=1198.65

Thus, the 29th percentile for the number of chocolate chips in a bag is 1198.65.

(b)

According to the Empirical rule 95% of the normally distributed data lies within 2 standard deviations of the mean.

P (μ - σ < X < μ + σ) = 0.95

P (1263 - 117 < X < 1263 + 117) = 0.95

P (1146 < X < 1380) = 0.95

Thus, the number of chocolate chips in a bag that make up the middle 95​% of bags are [1146, 1380].

(c)

The inter-quartile range of the normal distribution is:

IQR = 1.349 <em>σ</em>

Compute the inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies as follows:

IQR = 1.349 <em>σ</em>

      = 1.349 × 117

      = 157.833

Thus, the inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies is 157.83.

5 0
3 years ago
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