Answer: x=68/11 and y=-72/11
Steps:
2(x+4y=-20)
2x+8y=-40
2x - 3y = 32
- 2x + 8y = -40
-11y=72
y=-72/11
x + 4(-72/11) = -20
x - 288/11 = -20
x=68/11
(C) 6 + 3√3
<u>Explanation:</u>
Area of the square = 3
a X a = 3
a² = 3
a = √3
Therefore, QR, RS, SP, PQ = √3
ΔBAC ≅ ΔBQR
Therefore,


In ΔBAC, BA = AC = BC because the triangle is equilateral
So,
BQ = √3
So, BQ, QR, BR = √3 (equilateral triangle)
Let AP and SC be a
So, AQ and RC will be 2a
In ΔAPQ,
(AP)² + (QP)² = (AQ)²
(a)² + (√3)² = (2a)²
a² + 3 = 4a²
3 = 3a²
a = 1
Similarly, in ΔRSC
(SC)² + (RS)² = (RC)²
(a)² + (√3)² = (2a)²
a² + 3 = 4a²
3 = 3a²
a = 1
So, AP and SC = 1
and AQ and RC = 2 X 1 = 2
Therefore, perimeter of the triangle = BQ + QA + AP + PS + SC + RC + BR
Perimeter = √3 + 2 + 1 + √3 + 1 + 2 + √3
Perimeter = 6 + 3√3
Therefore, the perimeter of the triangle is 6 + 3√3
To solve these problems you need to use the quadratic formula which is listed below.

So, if you take #2.
The

has a 1 in front of it. The x has a -3 in front of it. The last number is also -3. So:
a = 1
b = -3
c = -3
Then you can plug all of these into the equation and simplify. Which gives you:
Answer:
linear functions will create a straight line when graphed but if you were to graph a non linear equation then it would not create a straight line
Step-by-step explanation:
Answer:
y = 70x + 20
Step-by-step explanation:
Let me know if I am right