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3 years ago

Find distance between parallel lines given equations in 3d

Mathematics

1 answer:

Lena [83]3 years ago

6 0

Does it have an image?

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The rate must be in DECIMAL form and the time must be in YEARS

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2 years ago

A pack of 8 batteries costs £4.99.

astra-53 [7]

Answer:

0.62

Step-by-step explanation:

4.99/8=0.62

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3 years ago

If −105 = −7 5 + 2 , then −2 =?

IgorLugansk [536]

Answer:

105 maybe

Step-by-step explanation:

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2 years ago

Read 2 more answers

(2, 7) and (-6, -2) find the distance between each pair of points

yaroslaw [1]

Answer:

$\sqrt{145}$

Step-by-step explanation:

Hi there!

We are given the points (2, 7) and (-6, -2). We want to find the distance between them. To do that, we can use the distance formula

The distance formula is given as $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We have 2 points, which is what we need to find the distance, but let's label their values to avoid any confusion

$x_1=2\\y_1=7\\x_2=-6\\y_2=-2$

Now substitute those values into the formula:

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\sqrt{(-6-2)^2+(-2-7)^2}$

Simplify the values under the radical:

$\sqrt{(-8)^2+(-9)^2}$

Raise to the second power:

$\sqrt{64+81}$

Add the numbers under the radical together

$\sqrt{145}$

The answer can be left as that, as the radical cannot be simplified.

Hope this helps!

7 0

2 years ago

Expressed as a product of its prime factors in index form, a number N is

Elena-2011 [213]

<u>ANSWER</u>

$5N^2=3^{2} \times 5^{5} \times x^{6}$

<u>EXPLANATION</u>

$N=3\times5^2 \times x^3$ .

$5N^2=5(3\times5^2 \times x^3)^2$

Recall this property of exponents;

$(a^m)^2=a^{m} \times a^m$

So our product becomes;

$5N^2=5(3\times5^2 \times x^3) \times (3\times5^2 \times x^3)$

$5N^2=5\times 3\times 3 \times 5^2 \times 5^2 \times x^3 \times x^3$

$5N^2=3\times 3\times 5 \times 5^2 \times 5^2 \times x^3 \times x^3$

Recall this law of exponents:

$a^m \times a^n =a ^{m+n}$

$5N^2=3^{1+1} \times 5^{1+2+2} \times x^{3+3}$

$5N^2=3^{2} \times 5^{5} \times x^{6}$

7 0

3 years ago